Write f(x) = 2x2 44x + 185 in vertex form. to write f(x) = 2x2 44x + 185, factor out from the first two terms. next, form a perf

Question

5 days ago

11

Write f(x) = 2x2 44x + 185 in vertex form. to write f(x) = 2x2 44x + 185, factor out from the first two terms. next, form a perf

ect square trinomial keeping the value of the function equivalent: f(x) = 2(x2 22x + 121) + 185 242 the function written in vertex form is f(x) = (x )2 + .

Mathematics

2 answers:

tester [3.9K] · Answer 1 · 2026-02-28T07:58:05+03:00

Conclusion:

To transform f(x) = 2x² – 44x + 185, start by factoring out 2 from the first two terms.

Next, create a perfect square trinomial while preserving the function's value:

f(x) = 2(x² – 22x + 121) + 185 – 242

The final expression in vertex form becomes f(x) = 2 (x – 11 )² + -57.

zzz [4K] · Answer 2 · 2026-02-28T07:58:49+03:00

zzz [4K]5 days ago

7 0

The equation is:
f(x) = 2x² - 44x + 185
f(x) = 2(x² - 22x + 121 - 121) + 185 =
= 2(x² - 22x + 121) - 242 + 185 =
= 2(x - 11)² - 57
Conclusion:
The vertex is located at (11, -57) and the vertex form is: f(x) = 2(x - 11)² - 57