I am hesitant to provide a definite answer since I'm not completely certain, but it's clear you can discard options C and D right away since the rate of change cannot be negative. Between options A and B, I would lean towards option B. I would have asked you to consider me the brainliest if I were correct, but I suspect this is for the IA4, where you're unable to check your grade... haha. Apologies, but I hope this assists you in some way!
Answer:
At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.
Step-by-step explanation:
A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.
The null and alternative hypotheses are:

The significance level is set at 0.10.
The sample mean recorded is 17, and the sample standard deviation is 5.37.
The degrees of freedom are calculated as df=(20-1)=19.
The t-statistic is:

The two-tailed P-value corresponding to t=1.67 is P=0.11132.
<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.
At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.
Response:
Detailed explanation:
The function
features a horizontal asymptote which is 
The function
presents a horizontal asymptote which is 
One function
lacks a horizontal asymptote because the degree of its numerator surpasses that of the denominator,
The function
displays a horizontal asymptote which is 