Find the value of x . 12.5,−10,−7.5,x ; The mean is 11.5 .

Answers:

C - The value of w cannot be negative.

D - The variable l is substituted with the value 20.

E - To isolate the variable w, the subtraction property of equality is applied.

~ .

<span>Which formula can be applied to find the side length of the rhombus?

 The correct answer is the first choice: 10/Cos(30°)

 Explanation:

 1. The figure shows a right triangle, where the hypotenuse is denoted by "x," and this is the length you are solving for. Therefore, you have:

 Cos(</span>α)=Adjacent side/Hypotenuse
<span>
 </span>α=30°
<span> Adjacent side=(20 in)/2=10 in
 Hypotenuse=x

 2. Inputting these numbers into the equation yields:
</span>
 Cos(α)=Adjacent side/Hypotenuse
<span> Cos(30°)=10/x

 3. Hence, by isolating the hypotenuse "x," you arrive at the expression to find the side length of the rhombus, as shown below:

 x=10/Cos(30°)
</span>

Response:

5.8%

Detailed reasoning:

For the business,

retail space rental = $2400

wages = $1800

utilities = $480

Total operating cost = $4680

However,

retail space rent decreased by 5%, which results in;

5% of $2400 = 0.05 x $2400 = $125

The new rental amount for retail space = $2400 - $125

                                             = $2275

wages were lowered by 6%, calculated as;

6% of $1800 = 0.06 x $1800 = $108

The revised wages = $1800 - $108

                           = $1620

Utilities experienced a 7% increase, calculated as;

7% of $480 = 0.07 x $480 = $33.6

The adjusted utilities cost = $480 + $33.6

                                               = $513.6

New total operating costs = $2275 + $1620 + $513.6

                             = $4408.6

The percentage change in monthly expenses = x 100%

                                    =

x 100%                                    = 5.8%

Jack swims a total distance of 9*25.0m=225.0 meters in 2 minutes and 34.5 seconds.

The time duration of 2 minutes and 34.5 seconds can be converted to seconds: 2*60sec +34.5 sec= 154.5 s


Jill completes 10*25.0m = 250 m also in 154.5 s.










Therefore,
the speed of Jack calculates to: 225.0 meters / 154.5 s =(225/154.5) m/s = 1.46 m/s

the speed of Jill calculates to: 250.0 meters / 154.5 s =(250/154.5) m/s = 1.62 m/s


Assuming both Jack and Jill start from point 0 moving in the positive direction,

an even number of lengths results in a Displacement of 0, while an odd number results in a Displacement of 25 m


Thus, Jill's average Velocity is 0,

and Jack's average velocity is 25/154.5 = 0.16 m/s

Answer:

Jack's Average Speed: 1.46 m/s

Jill's Average Speed: 1.62 m/s

Jack's Average Velocity: 0

Jill's Average Velocity: 0.16 m/s