Response:
the expected value of this raffle if you purchase 1 ticket = -0.65
Breakdown of the calculation:
Details:
5,000 tickets are sold at $1 each for a charitable raffle
Winners will be chosen at random with cash prizes as follows: 1 prize of $500, 3 prizes of $300, 5 prizes of $50, and 20 prizes of $5.
Therefore, the value and its respective probability can be calculated as follows:
Value Probability
$500 - $1 = $499 1/5000
$300 - $1 = $299 3/5000
$50 - $1 = $49 5/5000
$5 - $1 = $4 20/5000
-$1 1 - 29/5000 = 4971/5000
The expected value of the raffle when buying 1 ticket is computed as follows:





So, the expected value of this raffle when one ticket is purchased = -0.65
Calculating gives us 73 - 27 = 46
Next, 46 / 100 × 2628 = 1208
Adding together gives 2628 + 1208 = 3836
Solution:
In Mr. Skinner's class, the count of students bringing lunch from home is 12 out of 20.
Fraction of students who brought lunch from home in Mr. Skinner's class=
For Ms. Cho's class, the number who brought lunch from home is 14 out of 21.
Fraction of students who brought lunch from home in Ms. Cho's class=
Siloni is utilizing two spinners with 15 equal sections to randomly select students from the classes and predict whether they brought lunch or will purchase it from the cafeteria.
Number of Equal sections in each Spinner=15
To visualize the students from Mr. Skinner's class who brought lunch using a Spinner with 15 equal sections =
For Ms. Cho's class, using a Spinner with 15 equal sections =
Mr. Skinner's Class +1 = Ms. Cho's Class
This means that the spinner for Ms. Cho's class will include one additional section representing students who brought lunch.
Option A signifies that one additional section on Mr. Skinner's spinner represents students who brought lunch, reflecting Ms. Cho's class.
Purchasing the first 10 bricks at $4.50 each totals $45. The subsequent 10 bricks at $3.50 each add $35. This uses $80, leaving $20 to buy bricks priced at $2.50 each, allowing for 8 more bricks. Altogether, $100 can buy 28 bricks.
Thus, the algebraic expression representing the weight of coffee B is established. Given that x denotes the pounds of coffee A, the total weight for coffee A and coffee B adds up to 100 pounds, leading to an expression for coffee B's quantity.