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11 days ago

How many more shares in A&D than shares in peer comms ltd. Would you be able to buy with $500 in year 2?

Mathematics

1 answer:

babunello [3.6K]11 days ago

5 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct choice is the first option.

Step-by-step explanation:

According to the question,

The value of shares for A&D two years from now is $z =$ $150.

The value of shares for peer comms Ltd is $a =$ $275.

The additional amount of shares you can acquire from A&D compared to peer comms Ltd is

$L = 275 - 150$

$L =$ $125.

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When Joanne checked her Work by substituting the value of the variable back into the equation she got an answer of 12.34 equals

babunello [3607]

Answer:

Joanne might have utilized a rounded figure at a specific decimal point instead of the precise value. When validating her solution with a rounded figure, the outcome may not align precisely. The values, 12.34 and 12.33, are very similar, allowing Joanne to conclude that she correctly solved the multistep equation.

Step-by-step explanation:

Facts

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13 days ago

Read 2 more answers

Hailey paid \$13$13dollar sign, 13 for 1\dfrac3{7} \text{ kg}1 7 3 kg1, start fraction, 3, divided by, 7, end fraction, start

Zina [3893]

Answer:

The price per kilogram of salami amounts to = $9.1

Step-by-step explanation:

Given:

Hailey spent $13 on $1\frac{3}{7}$ kg of sliced salami.

We need to determine the cost per kg of the salami.

Solution:

We will use the unitary method to find the cost for one kilogram of salami.

If $1\frac{3}{7}$ kg of salami costs $13

Then the cost for 1 kg of salami in dollars = $13\div 1\frac{3}{7}$

When dividing mixed numbers, we convert them to fractions.

⇒ $13\div \frac{(7\times1)+3}{7}$

⇒ $13\div \frac{10}{7}$

To divide fractions, we take the reciprocal of the divisor and multiply.

⇒ $13\times \frac{7}{10}$

⇒ $\frac{13\times7}{10}$

⇒ $\frac{91}{10}$

⇒ $9.1$

Hence, the cost per kilogram of salami is = $9.1

3 0

11 days ago

Read 2 more answers

An urn contains 3 red and 7 black balls. Players and withdraw balls from the urn consecutively until a red ball is selected. Fin

Leona [4145]

Correct question:

An urn holds 3 red and 7 black balls. Players A and B take turns withdrawing balls until a red one is chosen. Calculate the probability that A picks the red ball. (A goes first, followed by B, with no replacement of drawn balls).

Answer:

The likelihood that A picks the red ball is 58.33 %

Step-by-step explanation:

A will select the red ball if it is drawn 1st, 3rd, 5th, or 7th.

1st draw: 9C2

3rd draw: 7C2

5th draw: 5C2

7th draw: 3C2

Calculating for all possible scenarios gives us:

9C2 = (9!) / (7!2!) = 36

7C2 = (7!) / (5!2!) = 21

5C2 = (5!) / (3!2!) = 10

3C2 = (3!) / (2!) = 3

Adding these possibilities results in 36 + 21 + 10 + 3 = 70.

The total outcomes for selecting a red ball = 10C3

10C3 = (10!) / (7!3!)

= 120.

The probability that A selects the red ball is determined by dividing the sum of possible events by the overall outcomes.

P( A selects the red ball) = 70 / 120

= 0.5833

= 58.33 %

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2 days ago

The steps to derive the quadratic formula are shown below: Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = − c Step 3 x2 + b over a ti

PIT_PIT [3895]

Answer:

$x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1:

$ax^2+bx+c = 0$

Step 2:

$ax^2+bx = -c$

Step 3:

$\frac{ax^2+bx}{a} = \frac{-c}{a}$

Step 4:

To complete the square, add $\frac{b^2}{4a^2}$ to both sides.

$x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}$

Step 5:

$x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-4ac+b^2}{4a^2}$

Step 6:

Taking square roots on both sides.

$x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}$

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23 hours ago

The value of y at x=-1in the equation 5y=2 is

Zina [3893]

Answer: y = 2/5 --> y = 0.4

Step-by-step explanation:

The equation 5y = 2 represents a horizontal line at y = 2/5.

This means that the y-coordinate holds the value of 2/5 = 0.4 for any x-coordinate.

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17 days ago