How many more shares in A&D than shares in peer comms ltd. Would you be able to buy with $500 in year 2?

Answer:

The formula to determine the distance Jane's trainer bikes is .

Detailed explanation:

A diagram has been included for clarity.

Known values:

Distance biked to the south = 16 miles

Distance ran west = 12 miles

We need to determine the distance covered by Jane's trainer.

Solution:

Let the biking distance be represented by 'x'.

We will assume it forms a right-angled triangle.

According to the Pythagorean theorem, it states that;

"The square of the hypotenuse is equal to the sum of the squares of the other two sides."

When set in equation form, this gives us;

Thus, the equation representing the distance biked by Jane's trainer is .

Upon solving, we find;

Consequently, Jane's trainer covers a distance of 20 miles.

Answer:

a) Null and alternative hypothesis

b) Point estimate d = -$78

c) Test statistic t = -2.438

P-value = 0.0113

Reject H0. This indicates that the average automobile premium in Pennsylvania is lower than in the nation.

Step-by-step breakdown:

This is a statistical test for the average population mean.

The hypothesis posits that car insurance in Pennsylvania is notably less expensive compared to the national average.

Accordingly, the null and alternative hypotheses are:

The significance level is set at 0.05.

The sample size is n=25.

The sample mean equates to M=1425.

A point estimate of the difference between the Pennsylvania mean premium and the national average can be computed using the sample mean:

Given that the standard deviation of the population is unknown, we approximate it using the sample standard deviation, which is s=160.

Then, we can calculate the t-statistic as:

The degrees of freedom for this sample size stand at:

This constitutes a left-tailed test, with 24 degrees of freedom and t=-2.438, rendering the P-value as (per a t-table):

As the P-value (0.0113) falls below the significance level (0.05), the results prove significant.

Thus, the null hypothesis obtains dismissal.

At a 0.05 significance level, there's sufficient evidence to assert that car insurance in Pennsylvania costs notably less than the national average.

Response:

Alan's survey aims to determine the art preferences among students at the local high school.

To conduct a thorough investigation, he needs to consider all students in the school as the target population since that is his goal.

Nevertheless, in many cases involving statistical studies, it's impractical to include the entire population. In such instances, a sample that accurately reflects the overall student body is employed.

This sample is a subset of the population and must share the same characteristics and attributes; otherwise, the findings may be skewed.

Thus, a feasible sample would consist of a specific number of students from each grade level, including freshmen, sophomores, juniors, and seniors. This approach ensures the sample accurately represents the larger population.

Answer:

Ants weigh approximately 118,615,000mg more.

Step-by-step explanation:

Based on a quick search, the average housefly weighs around 11.5mg, while an ant averages at 3.5mg. With these average weights, we can calculate the total weight of each species.

Flies: 3,990,000 * 11.5mg = 45,885,000mg

Ants: 47,000,000 * 3.5mg = 164,500,000mg

Consequently, it's clear that the 47 million ants possess a greater mass, specifically

164,500,000 - 45,885,000 = 118,615,000mg more