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lukranit
2 months ago
15

A 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. The force of the block on the Eart

h is: A. 35 N, down B. 35 N, up C. 14 N, down D. 14 N, up E. 49 N, up
Physics
1 answer:
Maru [3.3K]2 months ago
5 0

The moment the body impacts the ground, two types of Forces are produced: the gravitational pull and the Normal Force. This aligns with Newton's third law, indicating that every action has an equal and opposite reaction. If the downward force of gravity is directed toward the earth, the reactionary force from the block acts upwards, equivalent to its weight:

F = mg

Where,

m = mass

g = gravitational acceleration

F = 5*9.8

F = 49N

Consequently, the answer is E.

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A goose with a mass of 2.0 kg strikes a commercial airliner with a mass of 160,000 kg head-on. Before the collision, the goose w
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Response:

The change in momentum experienced by the goose during this encounter is 33.334 m/s

Explanation:

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airliner initial speed, u₂ = 870 km/hr = 241.667 m/s

The alteration in momentum is defined as;

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Using linear momentum conservation principles;

Total momentum pre-collision = Total momentum post-collision

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

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(2 x 16.667) + (160,000 x 241.667) = v (2 + 160,000)

38,666,753.334 = 160,002v

v = 38,666,753.334 / 160,002

v = 241.664 m/s

Thus, the final velocity of the bird is minimal in comparison to the final velocity of the airliner.

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The negative value indicates a slowdown in the bird following the collision.

Thus, the change in momentum of the goose during this interaction is 33.334 m/s

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