Response:
The change in momentum experienced by the goose during this encounter is 33.334 m/s
Explanation:
Provided;
goose's mass, m₁ = 2.0 kg
airliner mass, m₂ = 160,000 kg
goose's initial speed, u₁ = 60 km/hr = 16.667 m/s
airliner initial speed, u₂ = 870 km/hr = 241.667 m/s
The alteration in momentum is defined as;
ΔP = mv - mu
where;
u being the foremost velocity of the bird
v representing the concluding velocity of the bird
Using linear momentum conservation principles;
Total momentum pre-collision = Total momentum post-collision
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
v is the bird and airliner speed after collision;
(2 x 16.667) + (160,000 x 241.667) = v (2 + 160,000)
38,666,753.334 = 160,002v
v = 38,666,753.334 / 160,002
v = 241.664 m/s
Thus, the final velocity of the bird is minimal in comparison to the final velocity of the airliner.
ΔP = mv - mu
ΔP = m(v - u)
ΔP = 2(0 - 16.667)
ΔP = -33.334 m/s
The negative value indicates a slowdown in the bird following the collision.
Thus, the change in momentum of the goose during this interaction is 33.334 m/s