Boris's reaction time is denoted as t(r), implying that he has not jumped prior to that moment. Therefore, H(b)(t) equals 0
. The vertical displacement is determined simply as
D(t) = H(a)(t)
Answer:
The direction in which a vehicle accelerates aligns with its velocity direction. However, the force of acceleration works against the car's speed.
Explanation:
The car’s initial acceleration can be found using:
v = v₀ + a t
a = (v-v₀) t
which assumes the initial speed is zero (v₀ = 0 m/s).
a = v / t
a = 300 / t
The acceleration vector matches the direction of the vehicle's movement.
Upon hitting the wall, a force is exerted in the reverse direction to halt the car, thus this acceleration opposes the vehicle’s speed. However, the module should be much greater since the stopping distance is minimal.
<span>At ground level, the gravitational potential energy of any object is zero. To calculate potential energy, you multiply the object's height in meters by its mass in kilograms and the acceleration due to gravity to arrive at Joules.
Any object at ground level will have a potential energy totaling zero newtons since anything times zero equals zero. A mass of 54 kg situated 4 meters above ground possesses a gravitational potential energy of 2116.8 Joules.</span>
Answer:
a) 
b) the distance the motorcycle covers is 155 m
Explanation:
Let 
denote the variables. Next, we analyze the motion equation for the accelerating motorcycle alongside the constant speed of the car:
where:
represents the motorcycle's speed at time 2
is the steady velocity of the car
indicates the initial speeds of both vehicle types at time 1
d signifies the distance separating the car and motorcycle at the initial moment
x is the distance the car travels from time 1 to time 2
Solving the equations provides:
![\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dcar%26motorcycle%5C%5Cx%3Dv_0%5CDelta%7Bt%7D%26x%2Bd%3D%28%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%7D%29%20%5CDelta%7Bt%7D%5Cend%7Barray%7D%5Cright%5D)
For the second query, we determine x+d by applying the car’s motion equation to compute x:
Answer: Option D: indicates rapid travel with slow oscillation.
Clarification:
ycarrier(x,t) is traveling quickly but has slow oscillations.
