Answer:
A) 
denotes the resultant velocity of cart B post-collision.
B) 
C) 
D) 
E) 
F) Yes, kinetic energy remains conserved in this situation because both colliding bodies have identical mass.
G) Yes, momentum is conserved in every elastic collision.
Explanation:
Given:
- mass of car A,
- mass of car B,
- initial velocity of car A,
- final velocity of car A,
A)
The question mentions the cars experience an elastic collision:
By applying momentum conservation principles:
denotes the resulting velocity of cart B after collision.
B)
Initial kinetic energy of cart A:
C)
Initial kinetic energy of cart A:
D)
The final kinetic energy of cart A:
E)
The final kinetic energy of cart B:
F)
Yes, kinetic energy is conserved in this case due to both masses being identical in the collision.
G)
Indeed, momentum is consistently conserved in elastic collisions.
We apply the formula S=½gt², where S represents the vertical distance of 74.3m, and g is the acceleration due to gravity valued at 9.8 m/s². Therefore, t=√(2S/g)=3.884 seconds. Consequently, the car remains airborne for around 3.894 seconds. Its horizontal journey is vt=20×3.894=77.88m.
F = π/4 ρ d² v²
Explanation:
The formula for force is mass multiplied by acceleration:
F = ma
Acceleration is defined as the change in velocity over the change in time:
F = m Δv / Δt
Since there is no rebound effect, Δv is equal to v.
F = m v / Δt
Mass can be calculated as density multiplied by volume:
F = ρ V v / Δt
Flow rate describes the volume per time:
F = ρ Q v
Flow rate is determined by velocity multiplied by the cross-sectional area:
F = ρ (v A) v
This simplifies to F = ρ A v²
The area of a circle is calculated as pi times the square of the radius, or as pi/4 times the diameter squared:
F = ρ (π/4 d²) v²
Hence, F = π/4 ρ d² v²
(6-16)/4.0=-2.5 m/s²
The car's acceleration is -2.5 m/s²
Answer:
0.6
Explanation:
The formula for the volume of a sphere is 
Thus 
The radius of the disk is 
Applying angular momentum conservation;
The 
of the sphere = 
of the disk = 
= 0.6
