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vovangra
19 days ago
9

A manufacturer of cheese filled ravioli supplies a pizza restaurant chain. Based on data collected from its automatic filling​ p

rocess, the amount of cheese inserted into the ravioli is normally distributed. To make sure that the automatic filling process is on​ target, quality control inspectors take a random sample of 25 ravioli and measure the weight of cheese filling. They find a sample mean weight of 15 grams with a standard deviation of 1.5 grams. What is the margin of error at​ 90% confidence?
Mathematics
1 answer:
lawyer [9.2K]19 days ago
6 0

Answer:

At a confidence level of 90%, the margin of error is calculated to be 0.5133 grams.

Step-by-step explanation:

The formula for margin of error (E) is: (critical value × sample standard deviation) ÷ sqrt(n)

The sample standard deviation is 1.5 grams.

A 90% confidence level translates to 0.9.

Significance level is determined as 1 - C, which equals 1 - 0.9 resulting in 0.1 or 10%.

The sample size (n) is 25.

Degrees of freedom are calculated as n - 1, which is 25 - 1 equaling 24.

The critical value (t) for 24 degrees of freedom at a significance level of 10% is found to be 1.711.

Using these values, we calculate: E = (1.711 × 1.5) ÷ sqrt(25) = 2.5665 ÷ 5 = 0.5133 grams.

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DO, 0.75(x,y) signifies the dilation rule, where both x and y values are scaled by 0.75, indicating that the dilation, centered around the origin, has a scale factor of 0.75. The representation for this dilation would be,

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