Response:
The work performed by the particle traveling from x = 0 to x = 2 m totals 20 J.
Details:
The force impacting a particle, which is restricted to the x-axis, is expressed as follows:
We need to calculate the work done on a particle moving from x = 0.00 m to x = 2.00 m.
The formula for the work done by the particle is defined as:
Consequently, the work executed by the particle between x = 0 and x = 2 m amounts to 20 J. Thus, this is the solution sought.
Answer:
A. 30.7 cm
B.
C. The electric field points outward from the charge
Explanation:
A.
B.
Using Gauss's law
C. The electric field emanates away from the point of charge if the charge is positive.
Conclusion:
B) 225 m/s^2
Details:
The rock impacts the ground at 15m/s and penetrates 50cm=0.5m into the ground until it comes to a halt.
Assuming the acceleration is constant, the formula we will use is , which for acceleration is expressed as:
Assuming the downward direction is taken as positive (the direction of travel), both the initial velocity and displacement will be considered positive, and we substitute our values aligned with this movement:
The negative sign denotes upward direction.