Answer:
The tension in the string when the speed increased is 134.53 N
Explanation:
Given;
Tension in the string, T = 120 N
initial speed of the transverse wave, v₁ = 170 m/s
final speed of the transverse wave, v₂ = 180 m/s
The wave speed is expressed as;
where;
μ represents mass per unit length
The new tension T₂ will be computed as;
Consequently, the tension in the string when the speed was increased is 134.53 N
Answer:
The direction in which a vehicle accelerates aligns with its velocity direction. However, the force of acceleration works against the car's speed.
Explanation:
The car’s initial acceleration can be found using:
v = v₀ + a t
a = (v-v₀) t
which assumes the initial speed is zero (v₀ = 0 m/s).
a = v / t
a = 300 / t
The acceleration vector matches the direction of the vehicle's movement.
Upon hitting the wall, a force is exerted in the reverse direction to halt the car, thus this acceleration opposes the vehicle’s speed. However, the module should be much greater since the stopping distance is minimal.
Response:D
Clarification:
Provided
mass of object 
Distance traveled 
resulting velocity 
energy conservation occurs starting when the object begins its descent and reaches a speed of 12 m/s
Initial Energy
Final Energy
where 
is the work done by friction, if any
As friction is present, this indicates an open system with a net external force of zero.
An open system allows for the exchange of energy and mass, and the presence of friction indicates that it is indeed an open system.
B) 14.0 N
To address this inquiry, we need to evaluate the kinetic energy of the box before and after crossing the rough section. The kinetic energy is given by the formula:
E = 0.5 M V^2
where
E = Energy
M = Mass
V = velocity
Now, utilizing the known data, we compute the energy prior and post.
Before:
E = 0.5 M V^2
E = 0.5 * 13.5kg * (2.25 m/s)^2
E = 6.75 kg * 5.0625 m^2/s^2
E = 34.17188 kg*m^2/s^2 = 34.17188 joules
After:
E = 0.5 M V^2
E = 0.5 * 13.5kg * (1.2 m/s)^2
E = 6.75 kg * 1.44 m^2/s^2
E = 9.72 kg*m^2/s^2 = 9.72 Joules
Hence, the box consumed energy equal to 34.17188 J - 9.72 J = 24.451875 J over a length of 1.75 meters. Next, we will calculate the loss per meter by dividing the energy loss by the distance traversed.
24.451875 J / 1.75 m = 13.9725 J/m = 13.9725 N
When we round to one decimal point, we arrive at 14.0 N, which corresponds with option “B.”
Answer:
The number of photons emitted each second is
Explanation:
Let 'n' stand for the quantity of photons released by the bulb.
Provided Information:
The bulb radiates energy at a rate of 100 J per second (E).
Wavelength of emitted light is (λ) = 525 nm = 
The energy of a photon is calculated by:
Where,
Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,
To express in terms of 'n', we find:
Insert the provided values and solve for 'n'. The resulting calculation yields
Consequently,
photons are discharged every second.
