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ziro4ka
14 days ago
12

A 100 W incandescent lightbulb emits about 5 W of visible light. (The other 95 W are emitted as infrared radiation or lost as he

at to the surroundings.) The average wavelength of the visible light is about 600 nm, so make the simplifying assumption that all the light has this wavelength. How many visible-light photons does the bulb emit per second?
Physics
1 answer:
kicyunya [2.2K]14 days ago
6 0

Answer:

n = 1.89 x 10¹⁹ photons per second.

Explanation:

Given values:

Power of the bulb = 100 W

Visible light output = 5 W

Wavelength of visible light = 600 nm

Calculating the number of photons emitted each second:

Using the wavelength formula:

\lambda = \dfrac{c}{\nu}

\nu= \dfrac{c}{\lambda}

\nu= \dfrac{3 \times 10^8}{600 \times 10^{-9}}

\nu=5 \times 10^{14}\ Hz

Photon energy:

U = h υ

U = 6.63 x 10⁻³⁴ × 4 x 10¹⁴

U = 2.65 x 10⁻¹⁹ J

Determining the number of photons:

n = \dfrac{P}{U}

n = \dfrac{5}{2.65 \times 10^{-19}}

n = 1.89 x 10¹⁹ photons/s.

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The wavelength of light is 5000 angstrom. Express it in nm and m.
serg [2593]

Answer:

1 angstrom equals 0.1 nm.

To convert 5000 angstroms: 5000 angstrom = 5000 / 1 × 0.1 nm.

= 500 nm

1 \:  angstrom = 1 \times  {10}^{ - 10} m

To express 5000 angstroms in meters: 5000 angstrom = 5000 × 1 × 10^-10.

= 5 × 10^-7 m

Hope this explanation is useful for you.

7 0
1 month ago
Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your
inna [2210]

Answer:

The duration, t = 3.53 seconds

Explanation:

The following information is provided:

The equation to calculate the time t is expressed as:

t=(0.25)s^{1/2}...... (1)

Where

s denotes the distance in feet

We are to determine the duration taken by the stone to fall a distance of 200 feet, where s = 200 feet

Substituting the value of s into equation (1) yields:

t=(0.25)\times (200)^{1/2}

t = 3.53 seconds

Thus, the time taken by the object is 3.53 seconds, which provides the required answer.

4 0
25 days ago
A block moves at 5 m/s in the positive x direction and hits an identical block, initially at rest. A small amount of gunpowder h
Yuliya22 [2438]

Answer:

Speeds of 1.83 m/s and 6.83 m/s

Explanation:

Based on the law of conservation of momentum,

mv_o=m(v_1 + v_2)where m represents mass, v_o is the initial speed before impact, v_1 and v_2 are the velocities of the impacted object after the collision and of the originally stationary object after the impact.

5m=m(v_1 +v_2)

Thus, v_1+v_2=5

After the collision, the kinetic energy doubles, therefore:

2m*(0.5mv_o)=0.5m(v_1^{2}+v_2^{2})

2v_o^{2}=v_1^{2} + v_2^{2}

Substituting the initial velocity of 5 m/s provides the equation needed to proceed.v_o

2*(5^{2})= v_1^{2} + v_2^{2}We know that v_1+v_2=5 leads to v_1=5-v_2

50=(5-v_2)^{2}+ v_2^{2}

50=25+v_2^{2}-10v_2+v_2^{2}

2v_2^{2}-10v_2-25=0

Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25. v_2=6.83 m/s

By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.

6 0
12 days ago
A plane flying at 70.0 m/s suddenly stalls. If the acceleration during the stall is 9.8 m/s2 directly downward, the stall lasts
ValentinkaMS [2425]

Answer:

v = 66.4 m/s

Explanation:

We know that the aircraft starts off moving at a speed of

v = 70 m/s

now we have

v_x = 70 cos25

v_x = 63.44 m/s

v_y = 70 sin25

v_y = 29.6 m/s

in the Y direction, we can apply kinematic equations

v_y = v_i + at

v_y = 29.6 - (9.81 \times 5)

v_y = -19.5 m/s

as there is no acceleration along the x-axis, the velocity in this direction remains unchanged

thus yielding

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{63.44^2 + 19.5^2}

v = 66.4 m/s

4 0
24 days ago
Conductance is directly proportional to the length of a conductor. true false user: resistance is inversely proportional to the
inna [2210]
1) false

2) cross-sectional area of the conductor
7 0
2 days ago
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