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Alexxandr
2 months ago
8

A charged particle (q = −8.0 mC), which moves in a region where the only force acting on the particle is an electric force, is r

eleased from rest at point A. At point B the kinetic energy of the particle is equal to 4.8 J. What is the electric potential difference VB − VA?
Physics
1 answer:
Yuliya22 [3.3K]2 months ago
5 0

Answer:

V_B - V_A = 600 Volts

Explanation:

Given that the charge starts from rest and at point B has gained kinetic energy K = 4.8 J

we can apply the principle of conservation of mechanical energy, indicating that the increase in kinetic energy equals the reduction in electrostatic potential energy.

Thus, we can represent this as

U_B + KE = U_A

KE = U_A - U_B

4.8 = (-8 mC)(V_A - V_B)

4.8 = (8 \times 10^{-3})(V_B - V_A)

V_B - V_A = 600 Volts

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A rocket takes off vertically from the launch pad with no initial velocity but a constant upward acceleration of 2.25 m/s^2. At
kicyunya [3294]

Answer:

A) 328 m

B) 80.22 m/s

C) 8.18 sec

Explanation:

A)

The rocket's initial acceleration is 2.25 m/s²

Time until engine failure is 15.4 s

Initial velocity u during takeoff = 0 m/s

Distance covered while the engine is functional =?

We apply Newton's laws for this calculation

S = ut + \frac{1}{2}at^{2}

Here, S represents the distance traveled under the rocket's thrust

S = (0 x 15.4) + \frac{1}{2}(2.25 x 15.4^{2})

S = 0 + 266.81 m = 266.81 m

Before the engine fails, the final velocity can be found using:

v = u + at

v = 0 + (2.25 x 15.4) = 34.65 m/s

Once the engine fails, the rocket decelerates under gravitational pull at g = -9.81 m/s²  (acting downwards)

The upward initial velocity when freefall begins is v = 34.65 m/s

The final velocity is reached at peak height, where the rocket halts, therefore:

u = 0 m/s

The distance covered during this freefall will be s =?

Utilizing the equation

v^{2} = u^{2} + 2gs

0^{2} = 34.65^{2} + 2(-9.81 x s)

0 = 1200.6 - 19.62s

-1200.6 = -19.62s

s = -1200.6/-19.62 = 61.19 m

Thus,

Maximum Height = 266.81 m  + 61.19 m =  328 m

B)

At maximum height, the rocket’s initial upward velocity drops to 0 m/s (the rocket completely stops)

The descent occurs freely under g = 9.81 m/s² (acting downwards)

The distance covered during the fall will be 328 m

Final velocity v just prior to impact =?

Applying v^{2} = u^{2} + 2gs

v^{2} = 0^{2} + 2(9.81 x 328)

v^{2} = 0 + 6435.36

v = \sqrt{6435.36} = 80.22 m/s

The time taken before reaching the pad is found as follows

v = u + gt

80.22 = 0 + 9.81t

t = 80.22/9.81 = 8.18 sec

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2 months ago
Sally is pushing a shopping cart with a force of 20 N. Because the wheels are stuck, the friction caused by the ground is exerti
ValentinkaMS [3465]

The resultant force acting on the shopping cart is 12 N to the right.

This is a scenario related to Newton's Laws. A Free Body Diagram can be utilized to illustrate all the forces acting on the object. There are four forces at play:

  1. Gravity (g) acting downward.
  2. Normal force (N) acting upward.
  3. The force exerted by Sally (Fp) acting to the right.
  4. Friction force (Ff) acting to the left.

The first two forces (1 and 2) counteract one another as they are equal, while the overall force can be determined by combining forces (3) and (4)

F=Fp+Ff=20N+ (-8N)=12N

The positive value indicates that the shopping cart is moving towards the right.

Have a good day!

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Answer: Known facts are:

Sadie, the dam, is a black Labrador.

Sam, the potential sire, is a yellow Labrador.

Putting aside technical methods, the breeder can inspect the puppies for traits.

For instance, yellow coat color is recessive to black, so yellow pups would suggest Sam is likely the father; however black pups could also have Sam as sire if they inherited the mother's color alleles.

Examining coat color, conformation, and similar features is a reasonable starting point.

Ultimately these observations are probabilistic; the only definitive (scientific) method is a paternity (DNA) test.

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