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3 days ago

5

A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through th

e wire, it heats up and melts ice and snow on the window. For one window the wire has a total length of 12.2 m, a width of 1.8 mm, and a thickness of 0.11 mm. The wire is connected to the car's 12.0 V battery and draws 7.5 A. What is the resistivity of the wire material?

2 answers:

Softa [2K]3 days ago

7 0

Answer:

The answer is provided below.

Explanation:

Resistance calculated as voltage / current

R = V/I

= 12 / 7.5 = 1.6 ohms

R = pL/A

where p signifies resistivity

L = wire length, A = cross-sectional area

1.6 = p*12.2 / (1.6*10^-3*0.11*10^-3)

p = 2.3*10^-8 ohm - m

Thus, the resistivity of the material is 2.3*10^-8 ohm - m

ValentinkaMS [2.4K]3 days ago

7 0

Answer: 2.6*10^-8 Ωm

Explanation:

the length of the wire, l = 12.2 m

the width of the wire, w = 1.8 mm

the thickness of the wire, T = 0.11 mm

the potential difference of the battery, v = 12 V

the current in the battery, I = 7.5 A

Recall, Ohm’s law states, V = IR.

Hence, R = V/I

R = 12/7.5 = 1.6 Ω

Resistivity of a material is given by

ρ = RA/l

ρ = [1.6 * 1.8*10^-3 * 0.11*10^-3] / 12.2

ρ = (3.168*10^-7) / 12.2

ρ = 2.596*10^-8

Thus, the resistivity of the wire is 2.60*10^-8 Ωm

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