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sergejj
1 month ago
7

a closed tank is partially filled with glycerin. if the air pressure in the tank is 6 lb/in.2 and the depth of glycerin is 10 ft

, what is the pressure in lb/ft2 at the bottom of the tank

Physics
1 answer:
Ostrovityanka [3.2K]1 month ago
4 0

Answer:

note:

The solution is attached because of a calculation error. Please refer to the attachment.

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A skateboarder is attempting to make a circular arc of radius r = 16 m in a parking lot. The total mass of the skateboard and sk
kicyunya [3294]

To address this question, we will utilize concepts linked to centripetal force, aligning it with the static frictional force acting on the object. Using this relationship, we can derive the velocity and input the known values. The defined values are:

r = 16m

m = 82kg

\mu_s = 0.63

The maximum velocity can be determined using centripetal force,

F_c = \frac{mv^2}{r}

Should be equal to,

\frac{mv^2}{r} = \mu_s mg

v = \sqrt{\mu_s gr}

v = \sqrt{(0.63)(9.8)(16)}

v = 9.93m/s

As a result, the highest speed achievable through the arc without slipping is 9.93m/s

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A steady circular __________ light means drivers must stop at a marked stop line.
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B. red................
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1 month ago
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A proton is released from rest at the origin in a uniform electric field that is directed in the positive xx direction with magn
Ostrovityanka [3204]
The alteration in potential energy is  \Delta PE = - 3.8*10^{-16} \ J

In the query, it is stated that

  The intensity of the uniform electric field equals E = 950 \ N/C

     The distance the electron covers is  x = 2.50 \ m

Typically, the force exerted on this electron is expressed mathematically as

     F = qE

Where F signifies the force and  q represents the charge of the electron, which is a fixed value of q = 1.60*10^{-19} \ C

    Thus  

      F = 950 * 1.60 **10^{-19}

      F = 1.52 *10^{-16} \ N

Generally, the work-energy theorem is mathematically framed as

          W = \Delta KE

Where W denotes the work done on the electron by the electric field and  \Delta KE  is the change in kinetic energy

Additionally, work done on the electron can also be described as

        W = F* x *cos( \theta )

Where  \theta = 0 ^o assuming that the electron's movement aligns with the x-axis  

        So

             \Delta KE = F * x cos (0)

Inserting values

         \Delta KE = 1.52 *10^{-16} * 2.50 cos (0)

          \Delta KE = 3.8*10^{-16} J

According to the conservation of energy

       \Delta PE = - \Delta KE

Where \Delta PE signifies the change  in  potential energy  

Thus  

        \Delta PE = - 3.8*10^{-16} \ J

               

7 0
24 days ago
An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec
Yuliya22 [3333]
Energy can be determined using the formula power multiplied by time, thus for a power of 1200 W (or 1200 Joules per second) and a duration of 30 seconds, the calculation yields 36000 J or 36 kJ of electrical energy.

If you need the electrical charge or current: Power equals voltage times current. Therefore, with a power of 1200 watts and a voltage of 120 V, the current can be found as 1200 W divided by 120 V, which results in 10 Amperes. The charge is obtained by multiplying 10 A by 30 s, yielding 300 C.
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14 days ago
The acceleration of segment D is m/s2. Rank segments A, B , C from least accelerations to greatest acceleration. Least
Ostrovityanka [3204]

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

\frac{dy}{dx} = \frac{15m/s}{1s} = 15m/s^2

Segment B

\frac{dy}{dx} = \frac{5m/s}{1s} = 5m/s^2

Segment C

\frac{dy}{dx} = \frac{0m/s}{2s} = 0m/s^2

Segment D

\frac{dy}{dx} = \frac{-20m/s}{1s} = -20m/s^2

Sorted from the lowest to the highest acceleration:

D, C, B, A

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