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DerKrebs
7 days ago
8

(a) Find a vector-parametric equation r⃗ 1(t)=⟨x(t),y(t),z(t)⟩r→1(t)=⟨x(t),y(t),z(t)⟩ for the shadow of the circular cylinder x2

+z2=5x2+z2=5 in the xzxz-plane. Shadow: r⃗ 1(t)=r→1(t)= for 0≤t≤2π0≤t≤2π. (b) Find a vector-parametric equation for intersection of the circular cylinder x2+z2=5x2+z2=5 and the plane 3x+2y+8z=13x+2y+8z=1. Intersection: r⃗ 2(t)=r→2(t)= for 0≤t≤2π0≤t≤2π.
Mathematics
1 answer:
zzz [4K]7 days ago
6 0

Answer:

(a) r1(t) = <2cost, 0, 2sint>

(b) <2cost, (1 - 12sint - 10cost)/8, 2sint>

Step-by-step explanation:

x²+z²=4

a)

Within the xz plane, since y = 0...

Thus, x² + z² = 4 describes a circle centered at (0,0)..

This can be parameterized as

x = 2cos(t)

z = 2sin(t)

The necessary parameterization is:

r1(t) = <2cost, 0, 2sint>

b)

Cylinder equation: x² + z² = 4

Plane equation: 5x+8y+6z=1

Once again, the x² + z² = 4 can be parameterized as

x = 2cost, z = 2sint

Now, we can determine y using the plane equation...

5x+8y+6z=1

5(2cost) + 8y + 6(2sint) = 1

8y = 1 - 12sint - 10cost

y = (1 - 12sint - 10cost)/8

Thus, the parameterization becomes:

<2cost, (1 - 12sint - 10cost)/8, 2sint>

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