15. Find the values of x and y. (10x - 61)° (18y + 5)º (x + 10)

The process of subtracting polynomials resembles removing integers, as both involve regular subtraction. For instance, 3xy - 2xy results in 1xy. The same rules of subtraction apply when working with polynomials.

Thus, there are five distinct flavors. A group of 180 individuals was surveyed. Accordingly, the null hypothesis suggests no significant difference, with each flavor receiving 180/5 = 36 counts. x^2 = . Here, mi indicates the expected frequency based on the hypothesis, which is 36, n = 180, and xi corresponds to the actual observations. By substituting the known values, we find that x^2 = 9. The level of association is expressed as . This results in approximately 0.10, which surpasses our threshold.

Response:

The probability that a student has a pet, given they do not have any siblings is:

Option: D ( 60%)

Step-by-step breakdown:

Let A represent the situation where a student lacks a sibling.

Let B signify the occurrence that a student has a pet.

Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.

Let P denote the chance of an event happening.

We need to determine:

P(B|A)

From our knowledge:

From the data provided:

P(A)=0.25

and P(A∩B)=0.15

Thus,

which expressed as a percentage is:

Therefore, the probability is:

60%

The volume provided is 3Pi(x^3) with a radius of x. To determine the volume of a cone, the formula used is V= [1/3]Pi(r^2)*height. By substituting, we get [1/3]Pi(r^2)x = 3Pi(x^3). This simplifies to (r^2)x = 9(x^3). Eventually, we find that r^2 = 9x^2, which leads to r = sqrt[9x^2] = 3x. <span>Answer: r = 3x</span>

The translation rule can be expressed as T -3,1(x,y). The translation can also be indicated as (x,y)➡️(x-3,y+1).