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Gre4nikov
14 days ago
11

A sheet of gold leaf has a thickness of 0.125 micrometer. A gold atom has a radius of 174pm. Approximately how many layers of at

oms are there in the sheet?
Physics
1 answer:
Ostrovityanka [942]14 days ago
7 0

Response:

719

Clarification:

Conversion details

1 picometer (pm) corresponds to 1 × 10^{-12} meters

1 micrometer equals 1 × 10^{-6} meters

To calculate the quantity of layers, we will divide the total leaf thickness by the thickness of a single atom, thus dividing tex]0.125 × 10^{-6}[/tex] meters by 174 × 10^{-12} meters, resulting in approximately

\frac {0.125× 10^{-6}}{174\times 10^{-12}}=718.3908045\approx 719

Hence, there are roughly 719 sheets

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An object is moving in the plane according to these parametric equations:
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A rocket takes off vertically from the launch pad with no initial velocity but a constant upward acceleration of 2.25 m/s^2. At
kicyunya [1025]

Answer:

A) 328 m

B) 80.22 m/s

C) 8.18 sec

Explanation:

A)

The rocket's initial acceleration is 2.25 m/s²

Time until engine failure is 15.4 s

Initial velocity u during takeoff = 0 m/s

Distance covered while the engine is functional =?

We apply Newton's laws for this calculation

S = ut + \frac{1}{2}at^{2}

Here, S represents the distance traveled under the rocket's thrust

S = (0 x 15.4) + \frac{1}{2}(2.25 x 15.4^{2})

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v = u + at

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The upward initial velocity when freefall begins is v = 34.65 m/s

The final velocity is reached at peak height, where the rocket halts, therefore:

u = 0 m/s

The distance covered during this freefall will be s =?

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v^{2} = u^{2} + 2gs

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The time taken before reaching the pad is found as follows

v = u + gt

80.22 = 0 + 9.81t

t = 80.22/9.81 = 8.18 sec

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