The question lacks details. Here is the full question.
The accompanying image was captured with a camera capable of shooting between one and two frames per second. A series of photos was merged into this single image, meaning the vehicles depicted are actually the same car, documented at different intervals.
Assuming the camera produced 1.3 frames per second for this image and that the length of the car is approximately 5.3 meters, based on this information and the photo, how fast was the car moving?
Answer: v = 6.5 m/s
Explanation: The problem requires calculating the car's velocity. Velocity can be computed using:

Since the camera captured 7 images of the car and its length is noted as 5.3, the car's displacement is:
Δx = 7(5.3)
Δx = 37.1 m
The camera operates at 1.3 frames per second and recorded 7 images, thus the time driven by the car is:
1.3 frames = 1 s
7 frames = Δt
Δt = 5.4 s
<pconsequently the="" car="" was="" driving="" at:="">

v = 6.87 m/s
<pthe car="" moved="" at="" an="" estimated="">velocity of
6.87 m/s.
</pthe></pconsequently>
Answer:
A) and B) are valid.
Explanation:
When an object remains at rest, it is indicative that no net force acts upon it.
The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.
This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).
At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.
Thus, statements A) and B) are true.