3.113 A heat pump is under consideration for heating a research station located on Antarctica ice shelf. The interior of the sta

This involves circuit analysis through simplification of the resistors and capacitors. We need to determine the time constant for each circuit in figures A, B, C, D, and E. This leads to ranking the duration the bulbs remain lit from longest to shortest based on each circuit's time constant. The ranking for the time constants is C > A = E > B > D. Capacitance plays a pivotal role in electrostatics, and devices called capacitors are vital components in electronic circuits. When more charge is applied to a conductor, the voltage escalates proportionately. The capacitance of a conductor is quantified as C = q/v. Adding resistors in series raises resistance while parallel configurations reduce it, conversely increasing capacitance in parallel and diminishing it in series. Thus, circuits with greater time constants take longer to discharge.

Answer:

10m/s

Explanation:

Answer:

ΔL = MmRgt / (2m + M)

Explanation:

The system starts from rest, so the change in angular momentum correlates directly to its final angular momentum.

ΔL = L − L₀

ΔL = Iω − 0

ΔL = ½ MR²ω

To determine the angular velocity ω, begin by drawing a free body diagram for both the pulley and the block.

For the block, two forces act: the weight force mg downward and tension force T upward.

For the pulley, three forces are present: weight force Mg down, a reaction force up, and tension force T downward.

For the sum of forces in the -y direction on the block:

∑F = ma

mg − T = ma

T = mg − ma

For the sum of torques on the pulley:

∑τ = Iα

TR = (½ MR²) (a/R)

T = ½ Ma

Substituting gives:

mg − ma = ½ Ma

2mg − 2ma = Ma

2mg = (2m + M) a

a = 2mg / (2m + M)

The angular acceleration of the pulley is:

αR = 2mg / (2m + M)

α = 2mg / (R (2m + M))

Finally, the angular velocity after time t is:

ω = αt + ω₀

ω = 2mg / (R (2m + M)) t + 0

ω = 2mgt / (R (2m + M))

Substituting into the previous equations gives:

ΔL = ½ MR² × 2mgt / (R (2m + M))

ΔL = MmRgt / (2m + M)

Heat supplied to the gas = Q = 743 Joules

Work applied to the gas = W = -743 Joules

Additional explanation

The Ideal Gas Law that should be remembered is:

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Now, let’s proceed with the problem!

Given:

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

Unknown:

Work done on the gas = W =?

Heat supplied to the gas = Q =?

Solution:

Step A:

An ideal gas expands isothermally:

Next, we will determine the work performed on the gas:

Step B:

By utilizing the methodology mentioned earlier:

Next, we will ascertain the work completed on the gas:

Ultimately, we can calculate the total work done and heat supplied as follows:

Learn more

• Minimum Coefficient of Static Friction:
• The Pressure In A Sealed Plastic Container:
• Effect of Earth’s Gravity on Objects:

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

Explanation:

The formula illustrating the relationship between resistance and temperature is as follows:

R =

where,   R = final resistance

       

= initial resistance

       

= temperature coefficient of resistivity

       

= final temperature    

       

= initial temperature

Given data as follows.

     

     

      R = 36 ohm,  

= 3 ohm

         

= 0.0045

Substituting the provided values into the above formula gives us the following.

        R =

        36 =

     

=

                 = 7626.33 K

Thus, it can be concluded that the temperature of the light bulb at 12.0 V is 7626.33 K.