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Molodets
15 days ago
8

in 2016 the world's oldest tree was 5066 years old write the number that is 100 more using number name

Mathematics
2 answers:
zzz [12.3K]15 days ago
8 0

five thousand one hundred sixty-six

tester [12.3K]15 days ago
3 0

five thousand, one hundred sixty-six years old.

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2 tens and 76 ones equals
tester [12383]
It amounts to 96. I hope this was helpful.
5 0
16 days ago
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If u (x) = negative 2 x squared and v (x) = StartFraction 1 Over x EndFraction, what is the range of (u circle v) (x)?
tester [12383]
The range consists of negative values. The interval for the range is. It may be beneficial to review your functions as there seems to be no available choice that aligns with this outcome. Step-by-step explanation: Given functions, we need to determine the range of. As I evaluate the domain as well to see if it alters the range. For the function, we need to avoid division by zero, meaning that the domain excludes zero. Consequently, the domain encompasses all real numbers except zero. Overall, the final conclusion remains that the range is solely negative numbers.
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14 days ago
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On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl
lawyer [12517]

Answer:

0.40

Step-by-step explanation:

The percentage of members who engage only in long-distance running is 8%

Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08

The percentage of members who participate exclusively in field events is 32%

Thus, the probability of a member competing only in field events is P(B) = 0.32

The percentage of members acting as sprinters is 12%

So, the probability that a member is a sprinter is P(C) = 0.12

We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:

P(A or B) = P(A) + P(B)

Substituting the known values results in:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40

7 0
10 days ago
Mindy, a local artist, sells a piece of art at the pizza shop for $15, and the shop takes 15 percent commission. Instead of rece
lawyer [12517]
To tackle this problem, we first need to ascertain the commission taken by the pizza shop and how much money belongs to Mindy. We know that Mindy sells her artwork for $15, and the pizza shop retains a 15% commission. Therefore, the commission is calculated as (15/100) * 15, which equals 2.25 dollars. This means the pizza shop deducts $2.25 from each art sale made by Mindy. Consequently, the amount Mindy receives is (15 - 2.25), resulting in $12.75. Since Mindy opts not for cash but instead chooses a pizza valued at $12, including a 5% sales tax, it seems she benefits by $0.75 plus the pizza worth $12. Therefore, this arrangement appears fair for Mindy. Meanwhile, the pizza shop also makes an additional $2.25 from this transaction, making it equitable for both Mindy and the shop owner.
4 0
1 month ago
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Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number
tester [12383]

Answer:Part a) 2,50,18

Part b) When Jenny divides the square root of her favorite positive integer by \sqrt{2}, the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product results in an integer

thus

The number x=2could potentially be Jenny's favorite positive integer

2) For x=50

\sqrt{50}*\sqrt{2}=\sqrt{100}=10 -----> the product results in an integer

thus

The number x=50could potentially be Jenny's favorite positive integer

3) For x=18

\sqrt{18}*\sqrt{2}=\sqrt{36}=6 -----> the product results in an integer

thus

The number x=18could potentially be Jenny's favorite positive integer

Part B)

1) For x=2

\sqrt{2}/\sqrt{2}=\sqrt{1}=1 -----> the outcome is an integer

2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the outcome is an integer

3) For x=18

\sqrt{18}/\sqrt{2}=\sqrt{9}=3 -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2}, she obtains an integer as a result.

4 0
19 days ago
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