A table tennis ball with a mass of 0.003 kg and a soccer ball with a mass of 0.43 kg or both Serta name motion at 16 M/S calcula

Answer:

The air exiting from the hairdryer is moving at a speed of 10 m/s.

Explanation:

The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram

by substituting , into the equation and resolving for we find:

This thrust is linked to the speed of air ejection through the equation

where signifies the rate of air ejection, which is known to be

and since ,

by inserting these values into equation (2), we obtain the value of as:

resulting in

which indicates the air velocity discharged from the hairdryer.

Answer:

a) W =400 kJ

b) W = 0 kJ

c) W =-160.944 KJ

Explanation:

Given

Process 1 ---> 2

Pressure at point (1) P1 = 10 bar = P2

Volume at point (1) V1 = 1 m^3

Volume at point (2) V2 =4 m^3

For Process 2 ---> 3, where V = constant

Pressure at point (3) P3 = 10 bar

Volume at point (3) V3 = 4 m^3

Process 3 ---> 1 defined as PV = constant.

Required

Sketch the processes on the PV coordinates To calculate the work in kJ

Work is calculated by W=

a=V2

b=V1

x=Pdx=dV

W=

a=V3

x=4dx=dV

W=400 kJFor Process 2 ---> 3

As V = constant in this case, the volume remains unchanged, resulting in W = 0 kJ  

For Process 3 ---> 1  By applying point (1) --> 5 x.2 = C ---> C = 1 P = 5V^-1  

a=V1

x=1V^-1dx=dVsubstituting values into this integral results in

  = -160.944 KJ

Answer:

Explanation:

the provided information includes,

the charge of each of the two spherical drops = 0.1 nC

the potential on the surface = 300 V

when the drops combine into a larger drop

what is the surface potential of the new combined drop =?

radius = 0.003 m

volume =

=

= 2.612 × 10⁻⁷ m³

R = 0.00396 m