1950 g This is the result of lead being spread out in kilograms
<span>A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack.
centripetal force = weight of the ball
m v^2 / r = m g
v^2 / r = g
v^2 = g r
v = sqrt { g r }
v = sqrt { (9.80~m/s^2) (0.7 m) }
v = 2.62 m/s
Thus, the minimum speed for the ball at the top position is 2.62 m/s.</span>
Response:
D: The distance among the particles diminishes
Clarification:
Removing energy reduces the activity of molecules, similar to how one slows down in cold temperatures (I believe).
<span>First, apply Newton's second law of motion: F = ma.
Force equals mass times acceleration.
This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time,
we have force = (mass * velocity) / time,
leading us to conclude that (mass * velocity) / time will equal momentum / time.
Hence, we derive the equation mass * velocity = momentum.
Momentum = mass * velocity.
For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s,
Momentum = 6300 * 0.11,
resulting in P = 693 kg (m/s).
For the dolphin, having a mass of 50 kg and moving at 10.4 m/s,
Momentum = 50 * 10.4,
yielding P = 520 kg (m/s).
Thus, the elephant has a greater momentum (P) due to its larger size.</span>
Answer:
The work done, W = 19.6 J
Explanation:
It’s provided that
The mass of the block, m = 5 kg
The velocity of the block, v = 10 m/s
The coefficient of kinetic friction between the block and rough surface is 0.2
Distance traveled by the block, d = 2 m
As the block traverses the rough section, it loses energy equal to the work done by the kinetic energy.


W = 19.6 J
Thus, the change in kinetic energy of the block moving through the rough section is 19.6 J. Consequently, this is the required answer.