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Lynna
3 months ago
8

For years, space travel was believed to be impossible because there was nothing there Rockets could push off in space in order t

o provide the propulsion necessary to accelerate this inability to provide propulsion is because..
a) a space is a void of air so the rockets have nothing to push off.
b) gravity is absent in space.

c)a space is a void of wit so there is no air resistance in space.

d) nonsense! rockets do accelerate in space and have been able to do so for a long time.
​
Physics
1 answer:
Maru [3.3K]3 months ago
7 0

Rockets do indeed accelerate in the vacuum of space, something that has been possible for an extended period.

Response: Option D

Clarification:

A rocket's design aims to reach its destination by consuming fuel onboard. Hence, external forces are not necessary for motion in space. According to Newton's third law, action and reaction forces propel rockets free from Earth's gravity.

The remaining thrust needed for the rocket's journey in space comes from the combustion of fuel in its chambers. The fuel's combustion in designated compartments propels the rockets onward. Therefore, the belief that space exploration was impossible previously due to lack of propulsion mechanisms is a complete misconception.

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A small mass m is tied to a string of length L and is whirled in vertical circular motion. The speed of the mass v is such that
serg [3582]

Response:

(mv^2/R)/(mg)=1/2

v^2=R/2g

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A plane monochromatic radio wave (λ = 0.3 m) travels in vacuum along the positive x-axis, with a time-averaged intensity I = 45
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3 months ago
What is the freezing point of radiator fluid that is 50% antifreeze by mass? k f for water is 1.86 ∘ c/m?
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Ethylene glycol is known as the main component found in antifreeze.
The molecular formula for ethylene glycol is C₂H₆O₂.
Its molar mass is calculated as C₂H₆O₂ = (2×12) +(6×1) + (216) = 62g/mol
Given that antifreeze comprises 50% by weight, there exists 1 kg of ethylene glycol mixed with 1 kg of water.
ΔTf = Kf×m
ΔTf refers to the change in the freezing point.
= starting temperature of water - freezing temperature of the solution
= 0°C - Tf
= -Tf
Kf stands for the freezing point depression constant of water, which is 1.86°C/m
m is the molarity of the solution.
=(mass/molar mass) where mass of solvent is in kg
=1000g/62 (g/mol) /1kg
=16.13m
Substituting the value into the equation gives us
-Tf = 1.86 × 16.13 = 30
thus Tf = -30°C
7 0
2 months ago
Read 2 more answers
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