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hichkok12
2 months ago
13

A magnetron in a microwave oven emits electromagnetic waves with a frequency f-2450 MHz. What magnetic field strength is require

d for electrons to move in circular paths with this frequency?
Physics
1 answer:
kicyunya [3.2K]2 months ago
6 0

Answer:

Magnetic field strength, B = 0.073 Tesla

Explanation:

The problem gives that a magnetron in a microwave oven emits electromagnetic waves at a frequency of 2450 MHz, f=2450\times 10^6Hz.

We need to determine the magnetic field strength that allows electrons to orbit with this frequency.

The applicable formula is:

B=\dfrac{m\omega}{q}

Here, q represents the electron charge and m its mass.

B=\dfrac{9.1\times 10^{-31}\times 2\pi (2450\times 10^6)}{1.6\times 10^{-19}}

Calculating, we find B = 0.073 Tesla.

Therefore, this is the required magnetic field.

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Answer:

\Delta T = 0.81 ^oC

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According to the principle of energy conservation

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the resulting temperature change is expressed as

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\Delta T = \frac{25^2}{2\times 387}

\Delta T = 0.81^oC

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A rock is dropped from the top of a tall building. The rock's displacement in the last second before it hits the ground is 46 %
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The height measures 69.68 m

Explanation:

Given data

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Solution

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h = 4.9 t²....................2

For the first part of the inquiry

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0.54 h = 4.9 (t-1)²...................3

Thus,

Now we possess two equations with unknown variables

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The first equation already solves for h

Substituting h in the second equation allows us to find t

0.54 × 4.9 t² = 4.9 (t-1)²  

t = 0.576 s and  3.771 s

We choose here 3.771 s since 0.576 s is negligible; the distance covered in the last second before it impacts the ground is 46 % of the entire fall.

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6 0
1 month ago
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Answer:

Competitive forces model

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