Explanation:
The rate at which gases effuse is inversely related to the square root of their molar masses.
In this case, half of the helium (1.5 L) passed through the membrane in 24 hours. Therefore, we can calculate the effusion rate of He gas as follows.
= 0.0625 L/hr
Given that the molar mass of He is 4 g/mol and for
it is 32 g/mol.
Now,

= 2.83
Thus, the effusion rate of
= 
Rate of
= 0.022 L/hr.
This implies that 0.022 L of
gas will effuse in one hour.
Consequently, to find the duration needed for 1.5 L of
gas to effuse, we calculate as follows.
= 68.18 hours
Thus, we can conclude that it will require 68.18 hours for half of the oxygen to effuse through the membrane.