If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp

Answer:

Explanation:

In KCl, the two elements that combine to create KCl are potassium (K) and chlorine (Cl).

Potassium, as a Group 1 element, possesses one valence electron in its outermost shell which it readily donates during bonding. Every element aims to achieve a stable electron configuration, typically with 2 or 8 electrons in its outer shell. Potassium is characterized by its lower electronegativity and higher ionization energy, making it more likely to donate its electron than to accept one. On the other hand, chlorine belongs to Group 17 and has 7 electrons in its outer shell, requiring just one additional electron to complete its octet. Chlorine’s higher electronegativity and lower ionization energy facilitate its tendency to accept an electron rather than donate it.

The bond between potassium and chlorine that results in KCl is termed an electrovalent bond.

Reaction equation:

K + Cl → KCl

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This represents a chemical change because the substances' chemical identities were altered. The fizzing was a clear sign, and the temperature increase was another indicator of the reaction.

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Answer: The solution's pH post KOH addition is 3.84

Explanation:

Given information:

pH of buffer = 3.75

of formic acid = 3.75

Employing the Henderson-Hasselbalch equation for formate buffer:

Substituting values into the above equation yields:

Additional given information:

Concentration of formate buffer = 0.100 M

As the buffer volume remains constant, the concentration reflects the moles of formate ions and formic acid.

To find the number of moles based on the specified molarity, utilize the following equation:

Molarity of KOH = 1.00 M

Volume of solution = 5 mL

Incorporating these values into the equation gives:

The reaction between formic acid and KOH can be represented as:

Initial:       0.05    0.005               0.05

Final:         0.045          -                0.055          

The total volume of solution = 500 + 5 = 505 mL = 0.505 L    (Note:  1 L = 1000 mL)

To determine the pH of the acidic buffer, we can use the provided equation from the Henderson Hasselbalch:

Given information:

= the negative logarithm of formic acid's dissociation constant = 3.75

pH =?

Substituting values into the equation results in:

Consequently, the pH of the solution following KOH addition is 3.84