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xxTIMURxx
2 months ago
11

If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp

horus?
Chemistry
1 answer:
eduard [2.7K]2 months ago
8 0
 The ore contains a 55.4% composition of calcium phosphate (related to apatite), leading to a calculation where Ca3(PO4)2 equals 55.4%x=1000g, resulting in x=1000/0.554, which equals 1.805kg. To find the percentage of phosphorus in this amount of calcium phosphate, calculate the total masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95 (noting that oxygen contributes 16 mass x 4 =64), giving a cumulative mass of 310.2, while the phosphorus is 61.95 (Pmass x 2). Therefore, 61.95/310.2= 0.19 or 19% for phosphorus. Consequently, from 1.805 x 0.19, there will be 0.34kg of phosphorus.
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Substituting the value of moles from equation 2 into equation 1 yields:
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1 month ago
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8 0
1 month ago
Read 2 more answers
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