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Gelneren
4 months ago
13

A sample of H2SO4 contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. How many grams of sulfur and grams of o

xygen are present in a second sample of H2SO4 containing 7.27g if hydrogen
Chemistry
1 answer:
VMariaS [2.9K]4 months ago
7 0
Analyzing the formula for sulfuric acid reveals the molar proportions:

H: S: O
2: 1: 4

Next, we need to convert the provided mass of hydrogen into moles, calculated by:

Moles = mass / Mr
Moles = 7.27 / 1
Moles = 7.27

Thus, the number of moles for each element are:

S = 7.27 / 2 = 3.64 moles
O = 7.27 * 2 = 14.54 moles

Subsequently, the masses for sulfur and oxygen are:
S = 32 * 3.64 = 116.48 grams
O = 16 * 14.54 = 232.64 grams 
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What volume of co2 gas at 645 torr and 800. k could be produced by the decomposition of 45.0 g of caco3? caco3(s) → cao(s) + co2
KiRa [2933]
In the reaction: <span>caco3(s) → cao(s) + co2(g), it is evident that
1 mol (which is 100 g) of CaCO3 yields 1 mol (which is 44 g) of CO2
Now, the molarity of CaCO3 present in the reaction system is
</span>= \frac{weight of CaCO3 (g)}{gram molecular weight}
= \frac{45}{100} = 0.45 mol

Thus, 0.45 mol of CaCO3 leads to the formation of 0.45 mol of CO2.

According to the ideal gas equation, we have PV = nRT
V = \frac{nRT}{P}.
Considering P = 645 torr = 0.8487 atm (because 1 atm = 760 torr)
In that case, V = \frac{0.45 X 0.08206 X 800}{0.8487}

= 34.8 l
5 0
2 months ago
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