Answer:
Calcium's atomic radius is roughly 175 pm.
Explanation:
We know that magnesium has an atomic radius of 150 pm.
The atomic radius of strontium measures 200 pm.
Since calcium's position is between magnesium and strontium in group 2 of the periodic table, its atomic radius should be roughly averaged between magnesium's and strontium's atomic radii because atomic radius is not constant.
Thus;
Calcium's atomic radius is approximately calculated as follows;
The average atomic radius is (200 + 150)/2 = 175 pm.
The atomic number corresponds to the number of protons
Protons are denoted as P and Electrons as E P = E
The atomic mass equals the sum of Neutrons and Protons
Atomic number = atomic mass = neutrons
P = E
Atomic mass - atomic number = Neutrons
Example:
Calcium consists of 20 Protons 20P = 20E
Atomic mass - atomic number = neutron count:)
The reaction can be described as follows: CO + 2H2 = CH3OH. Given the specified quantities of the reactants, we will identify the limiting reactant and compute the remaining excess amount. Calculating, 1.50 x 10^-6 g CO converts to 5.36 x 10^-8 mol CO, while 6.80 x 10^-6 g H2 equals 3.37 x 10^-6 mol H2. Thus, CO is fully consumed in the reaction, leaving 3.37 x 10^-6 - 5.36 x 10^-8 = 3.32 x 10^-6 moles of gas.
Answer:
The result is "4,241.17 years"
Explanation:
The disintegration rate for C-14 atoms is indicated in 
The dissolution rate of the sample is given by 
The C-14 proportion within the sample can be determined as per 
With a half-life of 5730 years.
Now, we need to compute the number of half-lives (n) that are applicable:
Thus, the age of the sample is represented as = 
I hope you can decipher it and that it's also accurate. Wishing you all the best.
