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REY
2 months ago
6

Avanti works in a bookstore. She has four books and is going to place them in two stacks. The diagram above shows the books befo

re they touch. Use the information in the diagram to answer the question. How did the temperatures of the four books compare before they touched? How will the temperatures of the two top books compare after the books have been touching for a while, and why?
Chemistry
2 answers:
Anarel [2.9K]2 months ago
6 0

Answer:

There was no energy transfer when they were not in contact, and no energy was produced without motion. When stacked together, they generate momentum, resulting in kinetic energy.

Explanation:

I hope this is helpful

Anarel [2.9K]2 months ago
4 0

Response:

cocohggghehejieieieidiiriie

Clarification:

cocobhshsh

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Determine the percent yield for the reaction
Alekssandra [3086]

Answer:

The percent yield of Br₂ in this reaction amounts to 96.15%

Explanation:

The reaction's balanced stoichiometric equation is:

2 NaBr + 1 Cl₂ → 2 NaCl + 1 Br₂

To calculate the percent yield:

Percent yield = 100% × (Actual yield)/(Theoretical yield)

To determine the theoretical yield:

5.29 g of NaBr reacts with an excess of chlorine; therefore, NaBr is the limiting reagent, controlling the possible yield of products.

We convert 5.29 g of NaBr to moles.

Number of moles = (Mass)/(Molar mass)

Molar Mass of NaBr = 102.894 g/mol

Number of moles = (5.29/102.894) = 0.0514121329 = 0.05141 mole

According to the stoichiometry of the reaction:

2 moles of NaBr yield 1 mole of Br₂

Thus, 0.05141 mole of NaBr will produce (0.05141×1/2) mole of Br₂, which is 0.0257 mole of Br₂

Theoretical yield = Expected mass of Br₂ from the reaction

= (Number of moles) × (Molar mass)

Molar mass of Br₂ = 159.808 g/mol

Theoretical yield of Br₂ = 0.0257 × 159.808 = 4.108 g

Calculating the percent yield:

Percent yield = 100% × (Actual yield)/(Theoretical yield)

Actual yield = 3.95 g

Theoretical yield = 4.108 g

Percent yield = 100% × (3.95/4.108) = 96.15%

Hope this is helpful!!!

5 0
2 months ago
6.An acid-base indicator is usually a weak acid with a characteristic color in the protonated and deprotonated forms. Because br
Tems11 [2777]

Answer:

When HBCG and BCG^- are at the same concentration, the resulting color is green. This green shade initially becomes visible at a pH of 3.8.

Explanation:

HBCG serves as an indicator formed by dissolving solids in ethanol.

Since

Ka=[BCG−][H3O+][HBCG] When [BCG-] equals [HBCG], it follows that Ka = [H3O+].

<pWith a pH of 3.8,<pKa= [H3O+] = -antilog pH = -antilog (3.8)

Ka= 1.58 ×10^-4

5 0
2 months ago
Which statement best describes the direction of heat flow by conduction between two samples of the same material?
VMariaS [2998]

Response: 2. When molecules with different speeds collide, heat is transferred from the faster ones to the slower ones.

Clarification: I hope this was useful!:)

6 0
2 months ago
Read 2 more answers
Find the age ttt of a sample, if the total mass of carbon in the sample is mcmcm_c, the activity of the sample is AAA, the curre
castortr0y [3046]

Answer:

Explanation:

In a desert cave, an artifact has been discovered. The anthropologists investigating this artifact want to determine its age. They note that the current activity level of the artifact is 9.25 decays/s, and the carbon mass present is 0.100 kg. To ascertain the artifact's age, they will employ specific constants:

r=1.2

The formula for carbon 14 activity is

A=A_0e^{\lambda t}

where,

A_0 is the initial activity of the substance

Now, solve for t

-\lambda t=In\frac{A}{A_0}

t=-\frac{1}{\lambda} In(\frac{A}{A_0} )

=-\frac{1}{\lambda} In(\frac{A}{\lambda r(\frac{m_c}{m_a} )} )

since,

A_0=\lambda r(\frac{m_c}{m_a} )

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

Thus, the age of the artifact is

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

=-\frac{1}{1.21\times 10^{-4}} In(\frac{(9.25)(2.32\times 10^{-26}}{1.21\times 10^{-4}(\frac{1}{3.15569\times10^7} )(1.2\times 10^{-12})(0.100)}} )\\\\=6303.4 \ years

to two significant figures = 6300 years

4 0
2 months ago
A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6
alisha [2963]
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
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8 0
2 months ago
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