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Nezavi
1 month ago
15

A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6

1.0°C, what is the specific heat of the substance?
Chemistry
2 answers:
alisha [2.9K]1 month ago
8 0
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C
lions [2.9K]1 month ago
6 0

Information:

Mass of the unidentified material, m = 0.158 kg = 158 g

Heat intake Q = 2510.0 J

Starting temperature T1 = 32 C

Ending temperature T2 = 61 C

Required:

The specific heat capacity of the material

Analysis:

The heat required for the temperature increase from T1 to T2 is calculated as-

Q = mcΔT

where c represents specific heat

c = Q/mΔT = Q/m(T2-T1)

c = 2510 J / 158 g * (61 - 32) C = 0.548 J/gC

Result: The specific heat of the substance is 0.548 J/gC

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