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Katyanochek1
9 days ago
10

Determine the y component of reaction at a using scalar notation. express your answer to three significant figures and include t

he appropriate units.
Chemistry
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If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
eduard [2782]
 The ore contains a 55.4% composition of calcium phosphate (related to apatite), leading to a calculation where Ca3(PO4)2 equals 55.4%x=1000g, resulting in x=1000/0.554, which equals 1.805kg. To find the percentage of phosphorus in this amount of calcium phosphate, calculate the total masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95 (noting that oxygen contributes 16 mass x 4 =64), giving a cumulative mass of 310.2, while the phosphorus is 61.95 (Pmass x 2). Therefore, 61.95/310.2= 0.19 or 19% for phosphorus. Consequently, from 1.805 x 0.19, there will be 0.34kg of phosphorus.
8 0
2 months ago
From the Bohr equation in the introduction, the calculated energy of an electron in the sixth Bohr orbit of a hydrogen atom is
VMariaS [2998]

Answer:

= - 0.38 eV

Explanation:

According to Bohr's equation for the energy corresponding to an electron in the nth orbital,

E = -13.6 \frac{Z^{2} }{n^{2} }

Where E represents energy level in electron volts (eV)

Z symbolizes the atomic number of the atom

n denotes the principal quantum number

For n = 6

⇒ E = -13.6 × \frac{1^{2} }{6^{2} }

= - 0.38 eV

I hope this information helps.

4 0
2 months ago
Compound W, C8H17Br, and X, C8H17Cl, are products of the radical bromination (W), and chlorination (X), of 2,4-dimethylhexane. W
eduard [2782]

Respuesta:

Las posibles estructuras se muestran en la figura.

Explicación:

Los siete isómeros que se podrían formar a partir del compuesto dado debido a la halogenación radicalaria se ilustran en la figura.

Hemos mencionado solo el cloro como grupo para mostrar simplemente la naturaleza quiral del compuesto.

Un compuesto quiral tiene un carbono con los cuatro grupos diferentes entre sí.

Existen tres estructuras que son quirales (como se muestra).

W es el producto bromado

X es el producto clorado.

1) W reacciona fácilmente en agua para formar un producto de sustitución quiral Y, C8H17OH.

La reacción de un solo enantiómero de W produce un único enantiómero de Y como único producto de sustitución: lo que indica que la sustitución es SN2, lo cual es posible si el compuesto no es terciario.

2) X también reacciona fácilmente en agua, aunque a un ritmo más lento que W; de nuevo se forma un producto de sustitución quiral Z, C8H17OH. A diferencia de W, la reacción de un enantiómero de X produce Z que es casi racémico.

Esto significa que sufrirá una reacción SN1, por lo que el haluro de alquilo debe ser terciario.

Las posibles estructuras se presentan en la figura.

5 0
2 months ago
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