Answer:
0.008945 atm
Explanation:
In the reaction:
2H2S(g) ⇌ 2 H2(g) + S2(g)
Kp is defined as:
Where P represents the pressure of each component at equilibrium.
Starting with an initial pressure of H2S at 3.00 atm, the equilibrium concentrations are:
H2S = 3.00 atm - 2X
H2 = 2X
S2 = X
Substituting these values into the equation gives:
0 = 4X³ - 1.28x10⁻⁶X² + 1.92x10⁻⁶X - 2.88x10⁻⁶
Calculating X yields:
X = 0.008945 atm
In equilibrium, the pressure of S2 is X, so the pressure stands at 0.008945 atm
