Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
- The ionic compound must exhibit neutrality; its total charge should equal zero.
- A binary ionic compound is formed from two distinct ions.
Ca²⁺ combines with either Br⁻ or S²⁻ to create binary ionic compounds.
- CaS is created when Ca²⁺ pairs with S²⁻ resulting in the neutral binary ionic compound CaS.
- CaBr₂ results from the combination of one mole of Ca²⁺ with two moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
V⁵⁺ can also unite with either Br⁻ or S²⁻ to produce binary ionic compounds.
- V₂S₅ is formed when two moles of V⁵⁺ bond with five moles of S²⁻ yielding the neutral binary ionic compound V₂S₅.
- VBr₅ is produced by combining one mole of V⁵⁺ with five moles of Br⁻ to form the neutral binary ionic compound VBr₅.
Thus, the empirical formulas for four binary ionic compounds that may be produced are: CaS, CaBr₂, VBr₅, and V₂S₅.
Response:
0.8853 mL
Clarification:
Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:
- 13 lb *
= 5.902 kg
Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:
- 15 mg/kg * 5.902 kg = 88.53 mg
Finally, we compute the necessary mL of suspension, utilizing its concentration:
- 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL
Answer:
Explanation:
Considering the reaction: 2X + 3Y = 3Z, combining 2.00 moles of X with 2.00 moles of Y results in the production of 1.75 moles of Z.
2 mol 2 mol 1.75 mol
2X + 3Y = 3Z
2 mol is required with 3 mol to yield 3 mol.
3 mol Z / 3 mol Y = 1 to 1
should yield 2 mol Z
1.75 / 2 = 87.5 % production yield
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO
Solution:
Molality measures the concentration of a solute in a solution, defined by the amount of solute per specific mass of solvent.
Thus,
Molality = moles of solute / kg of solvent.
Therefore, kg of solvent = moles of solute / molality.
moles of solute = mass / molar mass
= 25.31 g / 101.1 g/mole
= 0.2503 mole.
kg of solvent = 0.2503 mole / 0.1982 m
= 1.263 kg
= 1263 g.
This is the final answer.