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Colt1911
2 months ago
12

A 24-ounce mocha beverage with whipped cream has 25% of the calories allowed on a 2,000-calorie-per-day diet. What percentage of

a 2,500-calorie-per-day diet would this same drink constitute?
5%
10%
20%
25%
Mathematics
2 answers:
Zina [12.3K]2 months ago
5 0

Answer:

It's quite straightforward, the correct option is c. Have a nice day!

Step-by-step explanation:


Leona [12.6K]2 months ago
3 0
To calculate the calorie count, we take 25% of 2000:
0.25 x 2000
= 500

Proportion of a 2500 calorie diet:
500/2500 x 100
= 20%

Thus, the beverage makes up 20% of a 2500 calorie daily intake.
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Harry put blue and green marbles in a bag. Exactly 3/4 of the marbles in the bag are blue. Which of the following could be the t
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Answer:

D

Step-by-step explanation:

When you multiply 3/4 by A, B, or C, it results in a decimal value; however, multiplying 3/4 by 8 yields 6, which is a whole number.

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2 months ago
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Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all
Svet_ta [12734]

Let the events be defined as follows:
A=Nathan suffers from an allergy
~A=Nathan does not suffer from an allergy
T=Nathan receives a positive test result
~T=Nathan does not receive a positive test result

According to the provided data,
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We aim to calculate the probability that Nathan is both allergic and tests positive
P(T n A)

Using the definition of conditional probability,
P(T|A)=P(T n A)/P(A)
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0.98 = P(T n A) / 0.75
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3 months ago
In isosceles △ABC (AC = BC) with base angle 30° CD is a median. How long is the leg of △ABC, if sum of the perimeters of △ACD an
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Important details about isosceles triangle ABC:

  • The median CD, which is drawn to the base AB, also acts as an altitude to that base in the isosceles triangle (CD⊥AB). This indicates that triangles ACD and BCD are congruent right triangles, each with hypotenuses AC and BC.
  • In isosceles triangle ABC, the sides AB and BC are equal, meaning AC=BC.
  • The base angles at AB are equal, m∠A=m∠B=30°.

1. Consider the right triangle ACD. The angle adjacent to side AD is 30°, which dictates that the hypotenuse AC is double the length of the opposite side CD relating to angle A.

AC=2CD.

2. Now, for right triangle BCD, the angle next to side BD is also 30°, so hypotenuse BC is twice the opposite leg CD linked to angle B.

BC=2CD.

3. To calculate the perimeters of triangles ACD, BCD, and ABC:

P_{ACD}=AC+CD+AD=2CD+CD+AD=3CD+AD;

P_{BCD}=BC+CD+BD=2CD+CD+AD=3CD+AD;

P_{ABC}=AC+BC+AB=2CD+2CD+AD+BD=4CD+2AD.

4. If the total of the perimeters of triangles ACD and BCD is 20 cm greater than the perimeter of triangle ABC, then

P_{ACD}+P_{BCD}=P_{ABC}+20,\\ \\3CD+AD+3CD+AD=4CD+2AD+20,\\ \\6CD+2AD=4CD+2AD+20,\\ \\2CD=20.

5. Given that AC=BC=2CD, the lengths of legs AC and BC of the isosceles triangles are 20 cm.

Answer: 20 cm.

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