If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a

Answer:

the speed value produced by the radar equipment.

Step-by-step explanation:

In an experiment, a random variable is typically referred to as a dependent variable. In this context, the random variable pertains to the speed value produced by the radar equipment. This value is reliant on the actual speeds of the cars that go past the equipment. A higher speed results in a greater value shown by the radar. Thus, it relies entirely on the automobiles.

Answer:

F' = (7, 6)

R' = (-1, 7)

I' = (-2, -5)

O' = (6, -6)

Step-by-step explanation:

The reflection rule across the y-axis states that (x, y) ---> (-x, y). Thus, all x coordinates must be converted to their negative counterparts. The -7 from F becomes 7, the 1 from R becomes -1, the 2 from I turns into -2, and the -6 from O changes to 6.

To calculate the mean absolute deviation of
1,2,3,4,5,6,7
, we start by finding the mean;
 (1+2+3+4+5+6+7) =28/7
                               = 4
. Next, we determine the absolute differences of each data point from the mean (x-μ)
 = -3,-2,-1,0,1,2,3
. The absolute values are 3,2,1,0,1,2,3
. Now we compute the mean of these absolute differences,
3+2+1+0+1+2+3 = 12
                           = 12/7
                           = 1.7143
. Thus, the mean is 4, and the Mean absolute deviation comes out to be 1.7143

x:200

x/200 =.2121212121...

200(x/200) = 200(.2121212121...)

x = 42.4242...

The expectation is that a player would achieve 42 hits over 200 at-bats.

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format or

For this question, we have

the point lies on the direct variation line

therefore

Determine the constant of proportionality k

-------> substitute ------>

The equation is

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point

Insert the values of x and y into the direct variation equation

-------> is valid

thus

the point lies on the direct variation line

case B) point

Insert the values of x and y into the direct variation equation

-------> is valid

thus

the point lies on the direct variation line

case C) point

Insert the values of x and y into the direct variation equation

-------> is not valid

thus

the point does not lie on the direct variation line

case D) point

Insert the values of x and y into the direct variation equation

-------> is valid

thus

the point lies on the direct variation line

case E) point

Insert the values of x and y into the direct variation equation

-------> is not valid

thus

the point does not lie on the direct variation line

case F) point

Insert the values of x and y into the direct variation equation

-------> is valid

thus

the point lies on the direct variation line

ultimately

the solution is