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blsea
2 months ago
13

If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a

point on the graph?
Since the function is even, the outputs of a negative x-value and a positive x-value are the same.

Since the function is even, the outputs of a negative y-value and a positive y-value are the same.

The graph has rotational symmetry, so the point will be reflected across the y-axis.

The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

PLEASE HELP IM IN THE MIDDLE OF A TEST
Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
4 0

If f(x) is categorized as an even function, then f(x)=f(-x). In this circumstance, f(6)=8=f(-6).


This indicates an even function has symmetry about the y-axis. Thus, the results of a negative x-value and a positive x-value are identical.


The appropriate choice is the first alternative.

As the graph is even, the outputs for a negative x-value and a positive x-value are congruent.


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A study1 conducted in July 2015 examines smartphone ownership by US adults. A random sample of 2001 people were surveyed, and th
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Answer:

a) Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}  

b) z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679  

c) z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58    

d) In this scenario, we notice that \hat p_1 > \hat p_2 thus the conclusion for this case would indicate

Step-by-step explanation:

Information provided

X_{1}=688 denote the number of men possessing smartphones  

X_{2}=671 signify the number of women possessing smartphones

n_{1}=989 group of men sampled

n_{2}=1012 group of women sampled

p_{1}=\frac{688}{989}=0.696 symbolize the proportion of men with smartphones

p_{2}=\frac{671}{1012}=0.663 symbolize the proportion of women with smartphones

\hat p denote the pooled estimate of p

z would denote the test statistic

p_v signify the value

Part a

The objective is to evaluate if there is a disparity in smartphone ownership between men and women; the hypothesis statements would be:  

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

Part b

The statistic relevant to this case is expressed as:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679  

Part c

By substituting the provided information, we find:

z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58    

Part d

In this instance, it is evident that \hat p_1 > \hat p_2 thus the conclusion for this case would seem

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