The series is 5 + 10 + 15 + 20 +... + 100 can be simplified as 5(1+2+3+...+20) which further equals 5{20(20+1)/2}. Using the formula for the sum of the first n natural numbers = n(n+1)/2, we find the sum to be 5{210} resulting in a total of 1050 .
Initially, we consider the number of natural numbers up to 100. Using the formula for the sum to n = (n(n+1))/2, with n = 100, we find that (100x101)/2 equals 5050, which will be denoted as value 'x'. Next, we look at the numbers divisible by 5, which include: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, and 100. Summing these yields 1050, which will serve as value 'y'. Subtracting x from y results in 5050 - 1050 = 4000. I hope this information is helpful.
The smallest whole-number value for x that works is 7. The triangle’s sides can be defined as: a = x, b = 2x, and c = 15. Recognizing c as the longest side leads us to the condition for an acute triangle: c^2 must be less than a^2 + b^2. Inputting the known values, we solve for x and find that x must exceed 6.708. As a result, the least integer that satisfies this requirement is 7.
34.56%. This is a binomial probability that can efficiently be calculated using the following formula: Here, n signifies the total number of trials (in this case, 4), x denotes the number of "successes" (which is 3), p is the success probability (60% or 0.6), and q indicates the failure rate (1 - p, thus 0.4). Plugging these values into the formula yields the solution: in percentage form, the probability is found to be 34.56%.