Answer:
60
Step-by-step explanation:
The function provided is:

The average rate of change of h(t) as time goes from t=a to t=b is expressed as:

This function can be reformulated as: 
The rocket's peak height is 231, which occurs at t=3.75 seconds.

The initial launch happens at: t=0
and 
The average rate of change from launch to max height is

Answer:
Circle diameter = 1.6 Cm
Detailed explanation:
Information provided:
Distance from the first to the third coin = 3.2 cm
Question to solve:
What is the diameter of each coin?
Calculations:
Total number of circles = 3
According to the diagram, the space between the first and third coins measures 3.2 cm.
Thus,
Space = radius of the 1st circle + diameter of the 2nd circle + radius of the 3rd circle
Space = radius of the 1st circle + 2 (radius) + radius of the 3rd circle
Space = R + 2R + R
3.2 Cm = 4 R
Radius = 0.8 Cm
Diameter = 2 × radius
Diameter = 2 × 0.8
Diameter = 1.6 Cm
Please clarify the question as I don't quite understand it.
Part A:
Please refer to the attached image to view the graph illustrating the inequalities.
There are two distinct lines shown, one with a steeper negative slope than the other. The shaded region in between indicates the solution set.
The green line corresponds to 2x+y≤8, while the blue line represents x+y≥4
Part B:
To determine if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it fails to satisfy either inequality, then it won't be part of the solution area.
2(8) + 10 ≤ 8
16 + 10 ≤ 8
26 ≤ 8... 26 is NOT less than or equal to 8
Hence, (8, 10) cannot be a solution because the inequality does not hold.
Part C:
I will select a random point from the graph, such as (2, 3). For your answer, any point within the shaded region where both x and y are positive would suffice.
The point (2, 3) indicates that Sarah can purchase 2 cupcakes and 3 pieces of fudge, ensuring that she acquires at least 4 pastries for her siblings while adhering to her 8 dollar budget.
Please let me know if you need any further clarification. Happy studying!