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Scorpion4ik
2 months ago
12

On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches

y = 0. It crosses the y-axis at (0, 6) and goes through (1, 2). Function g (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It goes through (negative 1, 2) and crosses the y-axis at (0, 6).
Which function represents g(x), a reflection of f(x) = 6(one-third) Superscript x across the y-axis?



g(x) = −6(one-third) Superscript x


g(x) = −6(one-third) Superscript negative x


g(x) = 6(3)x


g(x) = 6(3)−x

Mathematics
2 answers:
Zina [12.3K]2 months ago
8 0

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are provided with the information that

f(x)=6(\frac{1}{3})^x

Function f is decreasing as it moves from quadrant 2 to quadrant 1, tending towards y=0

It intersects the y-axis at the point (0,6) and goes through (1,2).

Function g(x) also approaches y=0 in quadrant 2, but increases in quadrant 1.

It passes through (-1,2) and crosses the y-axis at (0,6).

Reflection across y-axis:

The transformation rule is identified as

(x,y)\rightarrow (-x,y)

Applying this rule, we derive

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

Then, by substituting

x^{-a}=\frac{1}{x^a}

for x=-1

g(-1)=6\times (\frac{1}{3})=2

for x=0

g(0)=6

Consequently,g(x)=6(3)^x holds true.

zzz [12.3K]2 months ago
6 0

Answer:

The correct answer is A

Step-by-step explanation:

Check out my ifunny account "dankmemehistory"

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