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IrinaVladis
14 days ago
10

Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?

Mathematics
2 answers:
lawyer [9.2K]14 days ago
4 0
The solution is x = 6 + √21. The standard equation of a quadratic function is ax2 + bx + c = 0. Thus, the equation x2 = 12x – 15 can be rearranged to x2 - 12x + 15 = 0. Next, we move the constant term to the right side: x2 - 12x = -15. Here, b = 12, so (b/2)² = (12/2)² = (6)² = 36. We add this value to both sides: x2 - 12x + 36 = -15 + 36. Consequently, (x-6)² = 21. Taking the square root on both sides results in x - 6 = √21. Solving for x reveals that x = 6 + √21.
tester [8.8K]14 days ago
3 0
We are presented with the following polynomial: The initial step is to move the variables to one side of the equation. After doing this, we have: We complete the square by adding (b / 2) ^ 2 to both sides of the equation. After doing so, we obtain: Rewriting this gives us: Therefore, the solutions are: The solution set of the equation is:
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What is a31 of the arithmetic sequence for which a5=3.2 and a9=12.0?
zzz [9093]

The formula for an arithmetic sequence:

a_n=a_1+(n-1)d

We are given:

a_5=3.2,\ a_9=12.0

Determine d (the common difference)

a_9-a_5=4d\\\\4d=12.0-3.2\\\\4d=8.8\ \ \ |:4\\\\d=2.2

Calculate a31:

a_{31}=a_5+26d\\\\a_{31}=3.2+26\cdot2.2=60.4

7 0
27 days ago
The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
lawyer [9240]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Details: The cardiac output is assessed using the dye dilution technique with 3 mg of dye.

Goal: To determine the cardiac output value.

Solution:

Cardiac output formula:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Utilize integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Insert the value into 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Consequently, Cardiac output:F=0.055 L\s

4 0
18 days ago
At a hot air ballon festival, Erica spots a red ballon due east at an angle of elevation of 36 degrees. She turns due west and s
Zina [9179]

Answer:

Step-by-step explanation:

Information provided

The eastern balloon makes an elevation angle of 36^{\circ} and is positioned at a height of 461 m.

The western balloon creates an elevation angle of 51^{\circ} and is positioned at a height of 296 m.

Considering that Erica is 1.6 m tall, the effective height of the Red balloon becomes 459.4 m,

while the effective height of the Blue balloon ends up at 294.4 m.

Utilizing trigonometric principles,

\tan 36=\frac{459.4}{d_1}

\tan 51=\frac{294.4}{d_2}

d_1=632.30 m

d_2=238.4 m

Now calculating the distance separating the two Balloons,

d=d_1+d_2

d=870.70 m

7 0
20 days ago
Given f(x) = x3 – 2x2 – x + 2, the roots of f(x) are
PIT_PIT [9121]
The expression in question is:

f(x) = x³ – 2x² – x + 2

To determine the roots, follow these steps:

1. Set the equation to zero:

0 = x³ – 2x² – x + 2

2. Factor the equation to get:

(x-2)(x-1)(x+1) = 0

3. The roots can be identified as follows:

x1 = -1
x2 = 1
x3 = 2
3 0
27 days ago
Read 2 more answers
Students have organized
tester [8842]

Answer:

Part A. At least 6 hours

Part B. In less than 2.5 hours, Elijah will fall behind Mercedes

Part C. In over 2.5 hours, Elijah will lead Aubrey

Step-by-step explanation:

D = distance

v = speed

t = time

Formula connecting D, v, and t:

D=v\cdot t

Part A.

Steve's speed: v=3.5\ mph

Distance: a minimum of 21 miles

Time: unknown, so

3.5\cdot t\ge 21\\ \\35t\ge 210\ [\text{Multiplied by 10}]\\ \\t\ge \dfrac{210}{35}\\ \\t\ge \dfrac{30}{5}\\ \\t\ge 6

It would require Steve a minimum of 6 hours to traverse at least 21 miles on Day 1.

Part B.

Mercedes's speed: v_M=2.4\ mph

Elijah's speed: v_E=3.2\ mph

Elijah's Distance walked: D_E miles

Mercedes's Distance walked: D_M miles

Time: x hours

Mercedes is 2 miles ahead, therefore

D_E=3.2x\\ \\D_M=2.4x+2

Elijah will trail behind until

D_E

In 2.5 hours, Elijah will close the gap on Mercedes, and in less than 2.5 hours, Elijah will trail behind her.

Part C.

Aubrey's speed: v_M=3\ mph

Elijah's speed: v_E=3.2\ mph

Elijah's Distance walked: D_E miles

Aubrey's Distance walked: D_A miles

Time: x hours

At the beginning of Day 3, Elijah starts from Mile 42, while Aubrey begins at Mile 42.5.

D_E=42+3.2x\\ \\D_A=42.5+3x

Elijah will be ahead of Aubrey when

D_E>D_A\\ \\42+3.2x> 42.5+3x\\ \\3.2x-3x>42.5-42\\ \\0.2x>0.5\\ \\2x>5\ [\text{Multiplied by 10}]\\ \\x>\dfrac{5}{2}\\ \\x>2.5\ hours

In 2.5 hours, Elijah will surpass Aubrey, and after more than 2.5 hours, Elijah will outpace Aubrey.

4 0
1 month ago
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