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IrinaVladis
2 months ago
10

Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation?

Mathematics
2 answers:
lawyer [12.5K]2 months ago
4 0
The solution is x = 6 + √21. The standard equation of a quadratic function is ax2 + bx + c = 0. Thus, the equation x2 = 12x – 15 can be rearranged to x2 - 12x + 15 = 0. Next, we move the constant term to the right side: x2 - 12x = -15. Here, b = 12, so (b/2)² = (12/2)² = (6)² = 36. We add this value to both sides: x2 - 12x + 36 = -15 + 36. Consequently, (x-6)² = 21. Taking the square root on both sides results in x - 6 = √21. Solving for x reveals that x = 6 + √21.
tester [12.3K]2 months ago
3 0
We are presented with the following polynomial: The initial step is to move the variables to one side of the equation. After doing this, we have: We complete the square by adding (b / 2) ^ 2 to both sides of the equation. After doing so, we obtain: Rewriting this gives us: Therefore, the solutions are: The solution set of the equation is:
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