Answer:
The solution to your inquiry can be found below
Step-by-step explanation:
First method
20 = 5(-3 + x) expanding this equation
20 = -15 + 5x combine like terms
5x = 20 + 15
5x = 35 dividing by 5
5x/5 = 35/5
x = 7
Second method
20/5 = 5/5 (-3 + x) divide both sides by 5
4 = -3 + x adding 3 to both sides
4 + 3 = -3 + 3 + x simplifying
7 = x
Answer:
The triangulation technique may not always yield a precise result (aside from any errors in measurement) for the following reasons:
It employs a variety of data sources, different researchers, and multiple theories or viewpoints.
Step-by-step explanation:
Research triangulation integrates various methods, data sources, diverse investigators, and assorted theories to develop a deeper insight into the situations being studied. This process fortifies qualitative research by incorporating data from multiple sources, perspectives, and methodologies.
Sam needs to score 97 on his upcoming test to keep his average at 85. If you total 63, 84, 96, and 97, the sum is 340. Dividing 340 by four test scores yields an exact average of 85.
Answer:
CrO₃.
Step-by-step explanation:
First, we will find the chromium percentage in the oxide by using the following process:
Oxygen (O) = 48%
Chromium (Cr) =?
The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:
Cr = 100 – percentage of oxygen
Cr = 100 – 48
Cr = 52%
Next, we will determine the empirical formula for the oxide:
Chromium (Cr) = 52%
Oxygen (O) = 48%
Now, we divide by their molar mass:
Cr = 52/52 = 1
O = 48/16 = 3
Now, divide by the lowest value:
Cr = 1/1 = 1
O = 3/1 = 3
Thus, the empirical formula for the oxide is CrO₃.
Response:
Step-by-step breakdown:
For the null hypothesis,
H0: p = 88
For the alternative hypothesis,
Ha: p < 88
In terms of population proportion, where the probability of success is p = 0.88
q represents the probability of failure = 1 - p
q = 1 - 0.88 = 0.12
Considering the sample,
Sample proportion, P = x/n
Where
x = number of successes = 21
n = total samples = 32
P = 21/32 = 0.66
Next, we determine the test statistic, which represents the z-score
z = (P - p)/√pq/n
z = (0.66 - 0.88)/√(0.88 × 0.12)/32 = - 3.83
The relevant p-value corresponds by referencing the normal distribution table for the area falling beneath the z-score. As a result,
P value = 0.00006
