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joja
2 months ago
7

If the expected production volume when there are 120 workers is approximately 131,958 units, which of the following equations wo

uld provide a reasonable estimate of the 68% prediction interval for the output of those 120 workers?
Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
5 0

Answer:

Option 2

Step-by-step explanation:

A prediction interval at 68% for an output of 120 workers will be given by an interval that consists of +/- 1* standard error of regression. Thus, at a 68% PI, this would be computed as 131958 +/- 14994.93 which corresponds to option 2

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Svet_ta [12734]
The given road capacity is 3,500 vehicles per hour, and the expected number of vehicles arriving is 14,000. To calculate the time required for these vehicles to access the arena:
14,000 vehicles divided by 3,500 vehicles per hour equals 4 hours.

If the event is scheduled to commence at 7 p.m., the roads should close at: 7 p.m. minus 4 hours, which results in 3 p.m.
4 0
2 months ago
There are 28 people on a martial arts course. 13 are female and 15 are male. What fraction of the people are male? ​
lawyer [12517]

Answer:

15/28

Step-by-step explanation:

There are 28 participants total, with 15 being male, resulting in a fraction of 15/28

6 0
2 months ago
Alyssa is jogging near Central Park. She runs along 65th Street for about 0.19 miles, turns right and runs along Central Park We
zzz [12365]
Approximately 0.81 miles.
8 0
2 months ago
Read 2 more answers
What is a3 in an arithmetic sequence in which a10=41 and a15=61
zzz [12365]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_{10}&41\\
a_{11}&41+d\\
a_{12}&(41+d)+d\\
&41+2d\\
a_{13}&(41+2d)+d\\
&41+3d\\
a_{14}&(41+3d)+d\\
&41+4d\\
a_{15}&(41+4d)+d\\
&41+5d=61
\end{array}
\\\\\\
41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\
-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=10\\
a_{10}=41
\end{cases}
\\\\\\
41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

therefore

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=3\\
a_{1}=5
\end{cases}
\\\\\\
a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and you are probably aware of the amount.
8 0
1 month ago
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iven: C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the
Leona [12618]

Answer:

For a clearer understanding, refer to the attached figure:

Step-by-step breakdown:

1. According to the unique line postulate, only one line segment can be created: BC

This is because a single line can only connect two distinct points.

2. Utilizing the definition of reflection, reflect BC across l.

To identify the line segment reflected over l, we will apply the reflection definition.

3. Based on the reflection definition, C remains as its own image and A represents the image of B.

The reflection definition states that a figure is transformed into a mirror image around a line. Thus, CD serves as the perpendicular bisector of AB, which makes A and B equidistant from D, producing their mirror images.

4. Because reflections maintain length, we find that AC = BC

In a reflection, the figure transforms to create a mirror image, ensuring the lengths remain unchanged.

8 0
2 months ago
Read 2 more answers
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