I believe the correct response is option C.
Answer:
To inspect a batch consisting of 20 semiconductor chips, a sample of 3 is selected. Out of these, 10 chips fail to meet customer specifications.
a) Total distinct samples possible = 20C3 =
=1140
b) For exactly 2 good chips and 1 bad chip
Total samples = 10C2 * 10C1 = 45 * 10 =450
c) Combinations of 2 good 1 bad, 1 good 2 bad, and 3 bad chips
Total samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
= 
1.75
Step-by-step explanation:
idk tbh