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rodikova
11 days ago
8

Ellen does an experiment by releasing a ball from a height of 1 m above each floor in a tall building. She records the time it t

akes the ball to reach the floor.
Which question is Ellen most likely investigating?

How does distance affect the gravitational force on objects?
How does distance affect the electromagnetic force on objects?
Does height affect the strong force acting on a moving ball?
Does height affect the weak force acting on a moving ball?
Physics
2 answers:
serg [2.5K]11 days ago
7 0
The question Ellen is likely exploring is "In what way does distance influence the gravitational force acting on objects?"

Explanation:

inna [2.2K]11 days ago
4 0
The correct answer is A since I answered the question accurately
You might be interested in
A vacuum tube diode consists of concentric cylindrical electrodes, the negative cathode and the positive anode. Because of the a
serg [2593]

Answer:

   C = 4,174 10³ V / m^{3/4},  E = 7.19 10² / ∛x,    E = 1.5  10³ N/C

Explanation:

In this problem, we are tasked with determining the constant value and the generated electric field.

We will begin with computing the constant C:

           V = C x^{4/3}

           C = V / x^{4/3}

            C = 220 / (11 10⁻²)^{4/3}

            C = 4,174 10³ V / m^{3/4}

Next, we will find the electric field by utilizing the formula:

            V = E dx

             E = dx / V

             E = ∫ dx / C x^{4/3}

            E = 1 / C  x^{-1/3} / (- 1/3)

            E = 1 / C (-3 / x^{1/3})

We consider the evaluation from the lower limit x = 0 where E = E₀ = 0 to the upper limit x = x, resulting in E = E:

            E = 3 / C     (0- (-1 / x^{1/3}))

            E = 3 / 4,174 10³   (1 / x^{1/3})

           E = 7.19 10² / ∛x

Substituting x = 0.110 cm:

          E = 7.19 10² /∛0.11

          E = 1.5  10³ N/C

6 0
18 days ago
Jeff's body contains about 5.46 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells
ValentinkaMS [2425]

Answer:

a) Blood mass is m= 5.7876kg

b) The count of blood cells is  N_t=1.04*10^{13}

Explanation:

From the problem statement, we learn that

         The blood volume is  V_b = 5.46 \ L = \frac{5.46}{1000} = 0.00546m^3

         The density of blood is  \rho_b = 1060 kg/m^3

         % of blood which consists of cells is  = 45.0%

        the % of blood that is  plasma is  = 55.0%

        density of blood cells is  \rho_d = 1125kg/m^3

         % of cells that are white is  = 1%

        % of cells that are red is  = 99%

         The red blood cell diameter is  = 7.5 \mu m = 7.5*10^{-6}m

         The red blood cell radius is  = \frac{7.5*10^{-6}}{2} = 3.75*10^{-6}m

The mass is generally represented mathematically as

               m = \rho_b * V_b

Substituting values

            m = 1060 * 0.00546

               m= 5.7876kg

Cell mass is m_c = 45% of m

                         = 0.45 * 5,7876

                         = 2.60442 kg

The volume of cells is V_c = \frac{m_c}{\rho_d}

                                      = \frac{2.60442}{1125}

                                      = 2.315 *10^{-3} m^3

The white blood cells volume is V_w = 1% of the cells volume

                                                         = \frac{1}{100} * 2.315*10^{-3}

                                                       = 2.315*10^{-5}m^3

The volume of a single cell is V_s = 4 \pi r^3

                                                                        = 4*(3.142) * (3.75*10^{-6})^3

                                                                        = 2.21*10^{-16}m^3

The red blood cells volume is V_r = V_c - V_w

                                                           =2.315*10^{-3} - 2.315*10^{-5}

                                                           = 2.29*10^{-3}m^3

The total red blood cell count is  = \frac{V_r}{V_s}

                                                     = \frac{2.29 *10^{-3}}{2.21*10^{-16}}

                                                    = 1.037*10^{13}

The total white blood cell count is   =\frac{V_w}{V_s}

                                                          = \frac{2.315 * 10^{-5}}{2.21*10^{-16}}

                                                          = 1.04*10^{11}

The overall number of blood cells is  N_t= 1.037*10^{13} + 1.04*10^{11}

                                                        N_t=1.04*10^{13}

6 0
17 hours ago
Read 2 more answers
A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by
kicyunya [2264]

Answer:

W = -510.98 J

Explanation:

Force = 43 N, 61° SW

Displacement = 12 m, 22° NE

The work done is calculated using:

W = F*d*cos(A)

where A is the angle between the applied force and displacement.

The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°

Hence, W = 43 * 12 * cos(172)

This results in W = -510.98 J

The negative result indicates that the work is done contrary to the direction of the force applied.

6 0
18 days ago
What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?
Keith_Richards [2256]
Based on my findings, within a period of 2 hours, there are certain atoms remaining. N = N0 * 2^(-t/6.020) = N = N0 * 2^-0.33223 = 0.7943 N0 Thus, the quantity of atoms that undergo disintegration is N0 - N = N0 * (1 - 0.79430) = 0.2057 N0 This must equate to 15 mCi = 15 * 3.7 * 10^7 = 5.55 * 10^8 atoms N0 = 5.55 * 10^8 / 0.2057 = 2.698 * 10^9 atoms Consequently, 2.698 * 10^9 atoms represents the value of N0.
4 0
25 days ago
A plane monochromatic radio wave (λ = 0.3 m) travels in vacuum along the positive x-axis, with a time-averaged intensity I = 45
serg [2593]
The magnetic field is calculated to be -6.137 × T. Explanation: Given the radio wave wavelength of λ = 0.3 m and an intensity of I = 45 W/m² at times t = 0 and t = 1.5 ns, we determine Bz at the origin. We use the intensity formula relating to the electric field, which incorporates the known intensity of 45, the speed of light c = 3 × m/s², and ∈o as 8.85 × C²/N.m², leading us to E = 184.15. Consequently, applying the equations, we find B = -6.137 × T at the z-axis.
8 0
4 days ago
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