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morpeh
3 months ago
13

Use the terms "force", "weight", "mass", and "inertia" to explain why it is easier to tackle a 220 lb football player than a 288

lb football player.
Physics
2 answers:
ValentinkaMS [3.4K]3 months ago
7 0
<span>Answer
A person who weighs 220 lb has less mass than someone who weighs 288 lb, so accelerating the 220 lb player requires less force. The heavier player therefore carries greater momentum. Because 288 lb corresponds to more weight (and mass), that player has higher inertia and is harder to stop. For these reasons it is easier to tackle a 220 lb player than a 288 lb player. 
</span>
Sav [3.1K]3 months ago
6 0

Some key relationships to remember are:

Force = mass * acceleration

Weight = mass * gravity (10m/s)

Momentum = mass * velocity

Inertia is a property of mass: the tendency of an object to keep moving at the same velocity unless an outside force acts on it.

Using these formulas, if a 220 lb player and a 288 lb player run at the same speed, the 288 lb player has greater momentum and greater inertia than the 220 lb player. Consequently, changing the motion (speed or direction) of the 288 lb player requires more force (and therefore more energy) than changing the motion of the 220 lb player, which is why tackling the lighter player is easier.

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In concave mirror, the size of image depends upon
Maru [3345]

Answer:

The positioning of the object along the principal axis relative to the concave mirror.

Explanation:

In a concave mirror, the characteristics of the image generated depend on where the object is situated in relation to the mirror. The distance from the mirror to the object positioned along the principal axis is key.

The nearer the object is to the mirror, the larger or more magnified the image will appear. For example, placing an object between the focal point and the concave mirror's pole results in a significantly larger image compared to an object placed outside the center of curvature of the mirror.

8 0
2 months ago
Read 2 more answers
A dog of mass 10 kg sits on a skateboard of mass 2 kg that is initially traveling south at 2 m/s. The dog jumps off with a veloc
inna [3103]

Answer:

17 m/s south

Explanation:

m_1 Mass of the dog = 10 kg

m_2 Mass of skateboard = 2 kg

v = Combined velocity = 2 m/s

u_1 Velocity of the dog = 1 m/s

u_2 Velocity of skateboard

In this scenario, linear momentum is conserved

(m_1+m_2)v+m_1u_1+m_2u_2=0\\\Rightarrow u_2=-\dfrac{(m_1+m_2)v+m_1u_1}{m_2}\\\Rightarrow u_2=-\dfrac{(10+2)2+10\times 1}{2}\\\Rightarrow u_2=-17\ m/s

The speed of the skateboard post-dog jump will be 17 m/s south, considering north as the positive direction

3 0
1 month ago
Evaluate the final kinetic energy of the supply spacecraft for the actual tractor beam force, F(x)=αx3+βF(x)=αx3+β.
Sav [3153]

Answer:

K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x

Explanation:

To calculate the kinetic energy variation, we can utilize the work-energy theorem.

W = ΔK

∫ F .dx = K - K₀

If the object starts from rest, then K₀ = 0.

So, ∫ F dx cos θ = K.

As the force and displacement directions align, the angle is zero, and hence the cosine is 1.

Now we can substitute and perform integration:

α ∫ x³ dx + β ∫ dx = K.

Thus, α x⁴ / 4 + β x = K.

Next, we evaluate from the limits F = 0 to F:

α (x⁴ / 4 - 0) + β (x - 0) = K.

Consequently, K = αX⁴ / 4 + β x.

This results in K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x.

To finalize the computation, we need to ascertain the displacement.

8 0
3 months ago
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