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Anna11
1 month ago
11

A jar of sweets contains 5 yellow sweets, 4 red sweets, 8 green sweets, 4 orange sweets and 3 white sweets. Ola chooses a sweet

at random. What is the probability that she will pick either a yellow or orange sweet?
Mathematics
1 answer:
Zina [12.3K]1 month ago
7 0

Answer:

The probability of selecting either yellow or orange sweets is 3 / 8

Step-by-step explanation:

Given:

Count of yellow sweets = 5

Count of red sweets = 4

Count of green sweets = 8

Count of orange sweets = 4

Count of white sweets = 3

Find:

The chance of choosing a yellow or orange sweet

Computation:

Total number of sweets = 24

The probability for choosing a yellow sweet is 5 / 24

The probability for selecting an orange sweet is 4 / 24

The probability of selecting either yellow or orange sweets can be calculated as 5/24 + 4 / 24

This gives us a probability of 9 / 24 for either yellow or orange sweets.

The probability of selecting either yellow or orange sweets is 3 / 8

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Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Svet_ta [12734]

Response:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Detailed explanation:

In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:

Given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Applying the Poisson process, we find that

(a) at most 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) exactly 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) more than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) exactly 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) within the range of 10 to 15, inclusive

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
1 month ago
Which fraction is equivalent to StartFraction 2 Over 6 EndFraction? StartFraction 3 Over 7 EndFraction, because StartFraction 2
babunello [11817]
Which equivalent fraction corresponds to \frac{2}{6}? - \frac{3}{7} since \frac{2}{6}= \frac{2 + 1}{6 + 1} - \frac{3}{9} as \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

- \frac{3}{12} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

- \frac{3}{8} since \frac{2}{6}= \frac{1}{2} = \frac{2+1}{6+2} = \frac{3}{8}

The answer is

- \frac{3}{9} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

A fraction is deemed equivalent if it maintains the same value when expressed in simplest terms. The equivalent to \frac{2}{6} is found in the chosen option;

First, halve both the numerator and denominator by 2

\frac{2/2}{6/2}

Then reduce further

2/2 = 1 and 6/2 = 3; Thus;

\frac{2/2}{6/2} = \frac{1}{3}

Next, multiply both the numerator and denominator by 3

\frac{1*3}{3*3} = \frac{3}{9}

Therefore, \frac{2}{6} equals \frac{3}{9}.

7 0
13 days ago
Read 2 more answers
One is the additive identity. True or False
Inessa [12570]
False; the additive identity refers to the number 0, which does not alter the value of any number when added to it.
3 0
13 days ago
CHECK / HELP
babunello [11817]
The response states " No solution <<<" because these two lines are parallel and thus do not intersect
As we have 2=2 and 6≠2
Enjoy your day
7 0
24 days ago
Dos agricultores, padre e hijo, tardan 2 horas entre los dos arar un campo. Si solo el padre tarda 6 horas. ¿Cuanto tardara el h
Leona [12618]

Answer:

El hijo tardará solo 3 horas en completar el arado del terreno.

Detailing the process:

Sabemos que ambos tardan 2 horas en conjunto para labrar el campo, mientras que el padre lo hace solo en 6 horas.

Queremos determinar cuánto tiempo le llevará al hijo si trabaja solo.

Consideremos que el área del campo es x.

La tasa de trabajo conjunta de ellos es x/2.

La tasa de trabajo del padre es x/6, siendo y el tiempo que el hijo tarda. Por lo tanto, la tasa del hijo es x/y.

Sumando las tasas del padre y del hijo se obtiene la tasa de trabajo total. Así que tenemos:

x/6 + x/y = x/2.

Al despejar x, obtenemos 1/6 + 1/y = 1/2.

1/y = 1/2 - 1/6.

1/y = 1/3.

Por lo tanto, y resulta ser 3.

El hijo tardará 3 horas en labrar el campo.

8 0
1 month ago
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