Response: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Detailed explanation:
In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:
Given that
Applying the Poisson process, we find that
(a) at most 12
probability= 
(b) exactly 13
probability=
(c) more than 12
probability=
(d) exactly 20
probability=
(e) within the range of 10 to 15, inclusive
probability=
Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Which equivalent fraction corresponds to
? -
since
-
as
and
- 
because and
- 
since 
The answer is
- because and
A fraction is deemed equivalent if it maintains the same value when expressed in simplest terms. The equivalent to is found in the chosen option;
First, halve both the numerator and denominator by 2
Then reduce further
2/2 = 1 and 6/2 = 3; Thus;
Next, multiply both the numerator and denominator by 3
Therefore, equals .
False; the additive identity refers to the number 0, which does not alter the value of any number when added to it.
The response states " No solution <<<" because these two lines are parallel and thus do not intersect
As we have 2=2 and 6≠2
Enjoy your day
Answer:
El hijo tardará solo 3 horas en completar el arado del terreno.
Detailing the process:
Sabemos que ambos tardan 2 horas en conjunto para labrar el campo, mientras que el padre lo hace solo en 6 horas.
Queremos determinar cuánto tiempo le llevará al hijo si trabaja solo.
Consideremos que el área del campo es x.
La tasa de trabajo conjunta de ellos es x/2.
La tasa de trabajo del padre es x/6, siendo y el tiempo que el hijo tarda. Por lo tanto, la tasa del hijo es x/y.
Sumando las tasas del padre y del hijo se obtiene la tasa de trabajo total. Así que tenemos:
x/6 + x/y = x/2.
Al despejar x, obtenemos 1/6 + 1/y = 1/2.
1/y = 1/2 - 1/6.
1/y = 1/3.
Por lo tanto, y resulta ser 3.
El hijo tardará 3 horas en labrar el campo.
