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Feliz
1 month ago
7

A can of peas weighs 10 oz. Explain how you would make a graph to model the total weight of peas in terms of the number of cans

for up to 4 cans.
Mathematics
2 answers:
lawyer [12.5K]1 month ago
6 0

Response:

Example Response: Create a table that indicates the number of cans of peas as input, and the resulting total weight of the cans as output. Use 1, 2, 3, and 4 cans for the inputs, and find corresponding outputs of 10, 20, 30, and 40. Plot the ordered pairs from the table (input, output) onto the graph. Only quadrant I is necessary, as both x and y values will be positive

Step-by-step explanation:

brain list

babunello [11.8K]1 month ago
3 0
On the x-axis, represent the number of cans, while on the y-axis, denote the weight in ounces.

The x-axis (number of cans) should be labeled in increments of 1, ranging from 0 to 4
and the y-axis (weight) in intervals of 10, extending from 0 to 40

The equation would be: y = 10x
The points that lie on this line are: (0,0), (1,10), (2,20), (3,30), (4,40)
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Hours

Step-by-step explanation:

This is an incorrect figure.

5 0
2 months ago
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Value of sec Square 26 degrees - cot square 64 degrees is
Leona [12618]

Answer:

The value equals 1

Step-by-step explanation:

Consider the expression

sec^{2}(26\°)-cot^2(64\°)

Recall that

cot^2(64\°)=\frac{cos^2(64\°)}{sin^2(64\°)}

sec^{2}(26\°)=\frac{1}{cos^2(26\°)}

For two complementary angles A and B (where A+B=90°),

the identity is

cos(A) = sin(B)

Here, 26° and 64° are complementary angles, so

\frac{1}{cos^2(26\°)}=\frac{1}{sin^2(64\°)}

Substituting values,

\frac{1}{sin^2(64\°)}-\frac{cos^2(64\°)}{sin^2(64\°)}

\frac{1-cos^2(64\°)}{sin^2(64\°)}

From this, we find

1-cos^2(64\°)=sin^2(64\°)

By substitution,

\frac{sin^2(64\°)}{sin^2(64\°)}=1

4 0
3 months ago
A tank contains 24 gallons of water when all of a sudden the water begins draining at a constant rate of 2 gallons per hour. Let
AnnZ [12381]

Response:

a) V(t) = 24 - 2t

b) From t increasing from 3 to 6, v changes from 18 gallons to 12 gallons.

Detailed explanation:

The relationship between the tank’s volume and time is given by:

V(t) = V(0) - at

Where V(0) indicates the starting volume and a denotes the hourly decrease.

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The tank starts with 24 gallons of water, hence V(0) = 24

It drains steadily at 2 gallons each hour, therefore a = 2

Then

V(t) = V(0) - at

V(t) = 24 - 2t

b. When t progresses from 3 to 6, v changes from _________ to _________

V(t) = 24 - 2t

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6 0
3 months ago
There are seven boys and five girls in a class. The teacher randomly selects three different students to answer questions. The f
Svet_ta [12734]

The likelihood of selecting one girl is calculated as \frac{5}{12}. This is based on having 5 girls within a total of 12 students, and the probability of an event can be expressed as: \frac{\text{# of things you want}}{\text{# of things are possible}}.

Using the same reasoning, for the next student, we have reduced the number of students by 1, leading to 11 possible outcomes instead of 12, giving us:\frac{7}{11}, which represents the probability of selecting a boy as the second choice.

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However, we must combine these individual probabilities to determine the likelihood of this specific sequence of selections occurring:

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4 0
2 months ago
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Minato drove 390 miles. Part of the drive was along local roads, where his average speed was 20 mph, and the rest was along a hi
lawyer [12517]

Answer:

45 millas.

Explicación paso a paso:

Dado que la:

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Tiempo total = 8 horas

Designando la distancia recorrida por la vía local como L

y la distancia recorrida por la carretera como H

Por la vía local,

La Velocidad = distancia/ tiempo

20 = L / T

T = L /20.... (1)

Por la carretera,

Distancia recorrida H = 390 - L

Sea el tiempo = t

La Velocidad = distancia/tiempo

60 = (390 - L)/t

t = ( 390 - L)/60

Pero el tiempo total = T + t

<pEs decir

8 = L/20 + (390 - L)/60

<pEl MCM en el lado derecho sería 60<p8 = ( 3L + 390 - L )/60<pMultiplicamos en cruz

480 = 2L + 390

<pAgrupamos los términos semejantes

2L = 480 - 390

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L = 90/2

L = 45 millas.

<pAsí que la distancia que Minato recorrió por vías locales es de 45 millas

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