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11Alexandr11
1 month ago
3

A triangle has a base 12ft long and an altitude 8ft high. Find the area of the largest rectangle that can be inscribed in the tr

iangle so that the base of the rectangle falls on the base of the triangle.
-ans: 24 sq. ft.

Mathematics
1 answer:
AnnZ [12.3K]1 month ago
3 0
Greetings,

Let x represent the rectangle's length and y represent its height.

Applying Thales' theorem,

\dfrac{8-y}{8} = \dfrac{x}{12} \\

==\textgreater \ 8x=96-12y\\

==\textgreater \ y= 8 -\dfrac{2}{3} x\\

Aera=A(x)=x*y=x*( 8 -\dfrac{2}{3} x)=\dfrac{24}{3}*x-\dfrac{2}{3}*x^2\\

=-\dfrac{2}{3}*(x^2-12x)\\

=-\dfrac{2}{3}*(x^2-12x+36-36)\\

=-\dfrac{2}{3}*(x-6)^2+24\\

=24-\dfrac{2}{3}*(x-6)^2\\

=\dfrac{2}{3}*(72-2(x-6)^2)




\mbox{which is max if x=6 then y=8 - \dfrac{2}{3} *6=4} 





Maximum Area = 6*4 = 24 (ft²)



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