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Zigmanuir
2 months ago
8

In the quantum mechanical treatment of the hydrogen atom, which one of the following combinations of quantum numbers is not allo

wed?
a.) n=1; l=3; ml=0
b.) n=3; l=1; ml=-1
c.) n=3; l=2; ml=-1
d.) n=3; l=3; ml=2
e.) n=3; l=2; ml=2
Chemistry
1 answer:
alisha [2.9K]2 months ago
4 0
A) and d) are disallowed. The quantum number l must fall within the range of 0 to n - 1. For option a, where n = 1, the only possible value for l is 0. In option b, with n = 3, l can take values of 0, 1, or 2 (but not 3).
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The sample contains mc kg of carbon, leading to an activity measured as A/mc decay per kg. The variable r represents the initial mass of C-14 in the sample at t=0 relative to the total mass of carbon which is calculated as [(total number of C-14 atoms at t = 0) × ma] / total mass of carbon. Thus, N₀ equates to r/ma, which becomes equation 2.
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