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denpristay
4 months ago
15

Which of the following phrases describes valence electrons?

Chemistry
1 answer:
castortr0y [3K]4 months ago
7 0

Answer:

C

Explanation:

This is because valence electrons can be found in the outermost energy level.

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Which statement describes the location of metalloids on the periodic table? The metalloids are located below metals and above no
Tems11 [2777]
The metalloids include Boron, Silicon, and Germanium, and they are positioned to the right of metals and to the left of nonmetals. Since that is not available as an option, the most accurate description would be: The metalloids are situated below nonmetals and above metals in a group.
4 0
2 months ago
Read 2 more answers
If the aluminum block is initially at 25 ∘C, what is the final temperature of the block after the evaporation of the alcohol? As
Alekssandra [3086]

Explanation:

Los datos proporcionados son los siguientes.

       Calor de vaporización (\Delta H_{vap}) = 45.4 kJ/mol

       Capacidad calorífica (C_{p}) = 0.903 j/g^{o}C

Supongamos que el alcohol usado es C_{3}H_{8}O y su masa es 1.12 g. Además, la masa del bloque de aluminio es de 73.0 g.

Primero, calculamos los moles de alcohol (C_{3}H_{8}O) de la siguiente manera.

          Número de moles de alcohol = \frac{mass}{\text{molar mass}}

                                              = \frac{1.12 g}{60.1 g/mol}

                                              = 0.0186 mol

<pPor lo tanto, el calor absorbido por el alcohol (q_{alcohol}) es igual al calor perdido por el aluminio (q_{aluminium})

          n \times \Delta H_{vap} = -m \times C_{p} \times \Delta T

          0.0186 mol \times 45.4 kJ/mol = - 73.0 g \times 0.903 J/g^{o}C \times (T_{f} - 25^{o}C)

              12.71 = - (T_{f} - 25^{o}C)

                   T_{f} = 12.3^{o}C

Por lo tanto, podemos concluir que la temperatura final del bloque es 12.3^{o}C[/tex].

7 0
4 months ago
Calculate the volume of 12.0 g of helium at 100°c and 1.2 atm
Tems11 [2777]

Volume = nRT/P

n = number of moles (particles)

R = universal gas constant (0.0821)

T = temperature (in Kelvin)

P = pressure (in atm)

(Assuming there is 1 mole of Helium involved in the chemical reaction) we need to convert grams to moles: 12.0g He x 1 mol He/4 molar mass of He = 3 mol He.

Transform Celsius to Kelvin: 100*C + 273.15 = 373.15 K.

Now we can construct the volume equation: (3mol)(0.0821)(373.15)/1.2atm = 76.6 L of Helium gas.

8 0
4 months ago
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