The attached graph shows the moment when his catch surfaced at (35, 0). Given that it ascends consistently, the graph is linear. We need to establish the starting depth before he reeled it in. Using the equation d=rt, where d represents depth, r is the speed, and t is the time, we can find the distance traveled to reach the surface. Setting up the equation yields: d = 0.1(35). This indicates the catch traveled 3.5 m from a starting point of 3.5 m underwater, ascending at a rate of 0.1 m per second.
The equation of the perpendicular line can be identified by determining its slope and applying the given point within the standard formula.
Standard equation: y-y1 = m(x-x1)
m*m'=-1
where m' indicates the slope of the perpendicular line
m denotes the slope of the original line
m = -coefficient of x/coefficient of y = -4/-3 = 4/3
m' = -3/4
Substituting the point (3, -2):
y+2 = -3/4*(x-3)
4y+8 = -3x+9
Thus, the equation of the perpendicular line is: 3x+4y-1=0
In this problem the number we are working with is:
105,159
By definition we note:
thousand place: a five-digit quantity greater than zero.
Moreover, the rounding rule is:
if the digit being removed is 5 or more, increase the kept digit by one.
Therefore, rounding to the nearest ten thousand yields:
105,159 = 110,000
Answer:
105,159 rounded to the nearest ten thousand is:
105,159 = 110,000
Kevin, since the problem states a number (x) minus 20, and given that 20 is mentioned later, it indicates that it is the second number involved here.
