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Likurg_2
10 days ago
8

Patrick has 4 green hats, 3 blue hats, and 1 orange hat. If he selects a hat at random, what is the probability of selecting a g

reen hat?
Mathematics
1 answer:
Svet_ta [4.3K]10 days ago
5 0

Answer:

1/2

Step-by-step explanation:

To determine the total count of hats:

4 green hats + 3 blue hats + 1 orange hat = 8 hats

The probability of selecting a green hat is calculated as:

P(green hat) = number of green hats / total number of hats

                    = 4 / 8

                    = 1/2

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There is an integer n such that 2n2 − 5n + 2 is prime. To prove the statement it suffices to find a value of n such that (n, 2n2
Leona [4187]

Response:

n = 0 or 3

Detailed explanation:

2n² - 5n + 2

2n² - 4n - n + 2

2n(n - 2) -1(n - 2)

(n - 2)(2n - 1)

A prime number is defined as one that can only be divided by itself and 1

Setting n-2 = 1 gives n = 3

Setting 2n-1 = 1 gives n = 0

7 0
15 days ago
What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
Inessa [3926]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format y/x=k or y=kx

For this question, we have

the point (5,12) lies on the direct variation line

therefore

Determine the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

The equation is

y=\frac{12}{5}x

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point (0,0)

x=0\ y=0

Insert the values of x and y into the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is valid

thus

the point (0,0) lies on the direct variation line

case B) point (2.5,6)

x=2.5\ y=6

Insert the values of x and y into the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is valid

thus

the point (2.5,6) lies on the direct variation line

case C) point (3,10)

x=3\ y=10

Insert the values of x and y into the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not valid

thus

the point (3,10) does not lie on the direct variation line

case D) point (7.5,18)

x=7.5\ y=18

Insert the values of x and y into the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is valid

thus

the point (7.5,18) lies on the direct variation line

case E) point (12.5,24)

x=12.5\ y=24

Insert the values of x and y into the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not valid

thus

the point (12.5,24) does not lie on the direct variation line

case F) point (15,36)

x=15\ y=36

Insert the values of x and y into the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is valid

thus

the point (15,36) lies on the direct variation line

ultimately

the solution is

(0,0)

(2.5,6)

(7.5,18)

(15,36)


5 0
1 day ago
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Liam cuts a 48-inch piece of string into two pieces. One piece is 12 inches longer than the other. If s represents the length of
Inessa [3926]

Answer:

Here is the solution to the entire assessment: https://school.ckseattle.org/documents/2019/2/8_2_The_Pythagorean_Theorem_and_Its_Converse.pdf

Step-by-step explanation:

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3 days ago
Which table represents a linear function? A, B, C, D
tester [3938]

Answer:

Table B demonstrates a linear function.

Step-by-step explanation:

The reason Table B is classified as a linear function is that for each increment of one in x, y increases by a consistent rate of 4.

5 0
15 days ago
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Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
Leona [4187]

To address this problem, let's start by formulating the general motion equation along the vertical direction.

This gives us:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • g: gravitational acceleration
  • vo: initial velocity
  • h0: starting height

For the first individual:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second individual:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

When both individuals reach the identical altitude, the following holds:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rearranging results in:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Solving for time:

t = 29 (\frac {12} {19})\\t = 18.31s

Result:

The two window washers reach the same height after 18.31 seconds.

6 0
16 days ago
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