Have you discovered the solution yet? I'm a bit stuck.
The compound inequality for the temperature range protected by antifreeze is -40 < t < 284. Antifreeze operates effectively from −40°C to 140°C. By using 't' for temperature, the range in Celsius can be established as -40 < t < 140. The conversion formula for Celsius to Fahrenheit allows us to find the corresponding Fahrenheit temperatures for these Celsius values.
The sound intensity produced by the Pile Driver is approximately 39.5
which is close to 40 times that of a jackhammer.
Given the Loudness in dB for pile driver = 112 dB
we need to convert this into sound intensity.
To begin,
112dB/10 = 11.2
Now, we utilize this value as the exponent of 10
(10)^(11.2) = 1.5849 * 10 ^ 11
Next, we apply the formula of Watts per square meter to determine the intensity:
I / (10^-12 W/m^2) =1.5849 * 10 ^ 11
I = sound intensity = 0.158
We can then compare:
Sound intensity of Pile Driver/ Sound intensity of Jackhammer
(0.158) / (0.004)
= 39.5
or roughly 40 times the jackhammer.
The formula is Hx = ½ Wsin θ cos θ
The rationale behind this is:
By examining the torques on the bar, considering the hinge at the rotation axis, the equation constructed would be: ∑T = LT – (L/2 sin θ) W = 0
Thus, T = 1/2 W sin θ. For the forces acting on the bar, we have: ∑fx = Hx – T cos θ = 0. Inserting the value of T into the equation, the result is:∑T = LT – (L/2 sin θ) W = 0
