Solve the system. x + y = 8 2x2 – y = –5 Add the equations, then choose the result. 3x2 = –13 3x2 = 3 2x2 + x = 3 2x2 = –13

The diagram below illustrates the issue at hand.

Question 1:
The maximum area of the pool equals half the area of the circle.

To calculate the area of the circle: Area = πr², with r being half of the diameter.
Thus, Area of circle = π(60)² = 11309.73355 square feet.

Therefore, the area representing half the circle amounts to 11309.73355/2 = 5654.866... ≈ 5654.87 square feet (rounded to 2 decimal places).

Question b:

To find the pool's area, we take the circle's area and subtract the triangle's area.

The area of the circle is 11309.73 square feet.

For the triangle's area calculation: 1/2 × (60×103.92) = 3117.6 square feet.

The area of the pool thus operates as 11309.73 - 3117.6 = 7922.13 square feet.

Calculating the pool's volume: 7922.13 × 4 = 31688.52 cubic feet.

Note: Information related to the fish tank is unavailable, so the above calculation focuses solely on the entire pool's volume.

The translation rule can be expressed as T -3,1(x,y). The translation can also be indicated as (x,y)➡️(x-3,y+1).

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.

There are 2 beginner, 6 intermediate, and 3 advanced books, totaling 11.

P(advanced) = 3/11
replaced
P(beginner) = 2/11

P(both) = 3/11 * 2/11 = 6/121 <=

C. -31m⁴n - 8m²Step-by-step explanation:Given:(9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)Required:Identify an equivalent expression for itSolution:Distributing the negative sign across the parentheses results in:9mn - 19m⁴n - 8m² - 12m⁴n - 9mnNext, we combine like terms:9mn - 9mn - 19m⁴n - 12m⁴n - 8m²This simplifies to -31m⁴n - 8m²Thus, -31m⁴n - 8m² is the equivalent expression for (9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn).